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sp2606 [1]
3 years ago
8

Describe the end behavior of the given function. F(x) = (2/3)^x - 2

Mathematics
2 answers:
IgorC [24]3 years ago
7 0

Answer:

C. As x increases, f(x) approaches -2.

mote1985 [20]3 years ago
4 0

Answer:

C. As x increases, f(x) approaches -2.   -----

Step-by-step explanation:

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Given sample set A= {1,2,3,4,5} how many items are in the complement of set B if set B= all numbers greater than 2? OPTIONS : 3
Ostrovityanka [42]

Answer:

2

Step-by-step explanation:

It sounds like we are pretending A is the universe.  The only numbers in our world are 1,2,3,4, and 5.

You are given B is all numbers greater than 2.

The complement of B would all the elements not listed in B.

The elements in B are 3,4, and 5, since we are looking for numbers greater than 2 in our world of numbers above.

The elements not in B are 1 and 2.

So B complement is {1,2}.

There are 2 elements in our set for B complement. The elements that were counted were just the element 1 and the element 2.

6 0
3 years ago
If i have 480 grams of pasta for 4 people how many kilograms will i need for 14 people
Afina-wow [57]

\bf \begin{array}{ccll} \stackrel{pasta}{grams}&people\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 480&4\\ g&14 \end{array}\implies \cfrac{480}{g}=\cfrac{4}{14}\implies \cfrac{480}{g}=\cfrac{2}{7} \\\\\\ \cfrac{480\cdot 7}{2}=g\implies 1680=g

now, there are 1000 grams in one Kilogram, so in 1680 grams, there are 1680/1000 Kilograms, namely 1.680.

7 0
3 years ago
PLS HELPPPP MEEEE I NEED WORK SHOWN TOO
Elanso [62]

The series of operations for each case are listed below:

  1. GCF / GCF / GCF
  2. GCF / Grouping
  3. Quadratic trinomial
  4. GCF / Quadratic trinomial
  5. Difference of squares
  6. Difference of cubes / Quadratic trinomial
  7. Sum of cubes
  8. GCF / Quadratic trinomial
  9. GCF / Difference of squares

<h3>How to applying factor properties to simplify algebraic expressions</h3>

In algebra, factor properties are commonly used to solve certain forms of polynomials in a quick and efficient way and whose effectiveness is sustained on all definitions and theorems known in real algebra. In this problem, we should explain and show what factor properties are used in each case:

Case 1

5 · x · y³ + 10 · x² · y                                             Given

5 · (x · y³ + 2 · x² · y)                                            GCF

5 · x · (y³ + 2 · x · y)                                              GCF

5 · x · y · (y² + 2 · x)                                              GCF

Case 2

6 · z · x + 9 · x + 14 · z + 21                                   Given

3 · x · (z + 3) + 7 · (z + 3)                                       GCF

(3 · x + 7) · (z + 3)                                                  Grouping

Case 3

a² + 2 · a - 63                                                       Given

(a + 9) · (a - 7)                                                       Quadratic trinomial

Case 4

6 · z² + 5 · z - 4                                                     Given

6 · [z² + (5 / 6) · z - 2 / 3]                                      GCF

6 · (z - 1 / 2) · (z + 4 / 3)                                         Quadratic trinomial

Case 5

81 · m² - 25                                                           Given

(9 · m + 5) · (9 · m - 5)                                           Difference of squares

Case 6

8 · x³ - 27                                                               Given

(2 · x - 3) · (4 · x² + 6 · x + 9)                                  Difference of cubes

4 · (2 · x - 3) · [x² + (3 / 2) · x + 9 / 4]                      Quadratic trinomial

Case 7

27 · b³ + 64 · z³                                                      Given

(3 · b + 4 · z) · (9 · b² - 12 · b · z + 16 · z²)               Sum of cubes

Case 8

2 · w³ - 28 · w² + 80 · w                                         Given

2 · w · (w² - 14 · w + 40)                                          GCF

2 · w · (w - 4) · (w - 10)                                             Quadratic trinomial

Case 9

200 · a⁴ - 18 · b⁶                                                     Given

2 · (100 · a⁴ - 9 · b⁶)                                                GCF

2 · (10 · a² + 3 · b³) · (10 · a² - 3 · b³)                       Difference of squares

To learn more on polynomials: brainly.com/question/17822016

#SPJ1

7 0
1 year ago
A bathtub that holds 32 gallons of water contains 17 gallons of water. You begin filling it, and after 5 minutes, the tub is ful
Alik [6]
What’s the question???
8 0
2 years ago
Read 2 more answers
Use the diagram to find the height of statue.round to the nearest tenth
jeyben [28]

Answer:

7.3 ft

Step-by-step explanation:

The information given represents a right angle triangle with the following:

reference angle = 52°

Adjacent side length = 5.7 ft.

Opposite side length = height of the statue = h

Applying the trigonometric ratio formula, we would have:

tan(52) = \frac{h}{5.7}

Multiply both sides by 5.7

tan(52) \times 5.7 = \frac{h}{5.7} \times 5.7

tan(52) \times 5.7 = h

h = 7.3 ft (nearest tenth)

6 0
2 years ago
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