Answer:
214
Step-by-step explanation:
The set up would be x + (x + 1) + (x + 2) + (x + 3) = 854, naturally as the numbers are consecutive. Solving for x:
x + (x + 1) + (x + 2) + (x + 3) = 854,
x + x + 1 + x + 2 + x + 3 = 854,
4x + 1 + 2 + 3 = 854,
4x + 6 = 854,
4x = 854 - 6 = 848,
x = 848/4 = 212
The third number then should be 212 + 2 = 214
Given:
The values are 
.
To find:
The values of 
and 
.
Solution:
We have,
...(i)
Multiply both sides by 10.
...(ii)
Subtracting (i) from (ii), we get
And,
Now, the product of a and b is:
The quotient of a and b is:
Therefore, the required values are and .
The number of times I would expect to roll a number that is not a 5 is 300 times.
<h3>What is the number of times a 5 won't be rolled?</h3>
A standard die has 6 faces. There are 5 numbers that are not 5 on a standard die. They are 1, 2, 3, 4, 6.
The number of times a 5 won't be rolled = (5/6) x 360
5 x 60 = 300 times
To learn more about a standard die, please check: brainly.com/question/20376457
#SPJ1
Answer: A
Step-by-step explanation: I think its A because < means less than. So y is less than z. I hope that helps.
