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Snezhnost [94]
3 years ago
11

Help me please!!!..​

Mathematics
1 answer:
12345 [234]3 years ago
4 0

Step-by-step explanation:

HERE,

as,it is a right angle triangle,

x=\tt{\sqrt{8^2+6^2}   }

\tt{ x=\sqrt{64+36}  }

\tt{ x=\sqrt{100}  }

\tt{x=10km.    }

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Daniel wrote the following two-column proof for the given information.
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The information given about the proof does that Daniel made an error on line 2.

<h3>How to illustrate the information?</h3>

Given:

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2. AB + BC = AC      incorrect (not an angle angle addition postulate)

3. 3x+2 + 4x + 8 = 38         correct

4. 7x + 10 = 38                    correct

5. 7x = 28                           correct

6. x = 4

Daniel made an error on line 2.

Here is the complete question:

Daniel wrote the following two-column proof for the given information. Given: AB = 3x + 2; BC = 4x + 8; AC = 38 Prove: x = 4 Statements Reason 1. AB = 3x + 2; BC = 4x + 8; AC = 38 1. Given 2. AB + BC = AC 2. Angle Addition Postulate 3. 3x + 2 + 4x + 8 = 38 3. Substitution Property of Equality 4. 7x + 10 = 38 4. Combining Like Terms 5. 7x = 28 5. Subtraction Property of Equality 6. x = 4 6. Division Property of Equality On which line, did Daniel make his error? line 2 line 3 line 4 line 5

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Answer:

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Then you find the ratio:

The length of the arc is 90/360, which is 1/4, of the circumference.

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Step-by-step explanation:

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