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Snezhnost [94]
2 years ago
11

Help me please!!!..​

Mathematics
1 answer:
12345 [234]2 years ago
4 0

Step-by-step explanation:

HERE,

as,it is a right angle triangle,

x=\tt{\sqrt{8^2+6^2}   }

\tt{ x=\sqrt{64+36}  }

\tt{ x=\sqrt{100}  }

\tt{x=10km.    }

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A number is six greater than 12 times another number the sum of the two numbers is 214 find both numbers
stich3 [128]
Let x and y represent the two numbers.
.. x = 6 +12y . . . . . one number is 6 greater than 12 times another
.. x + y = 214 . . . . their total is 214

Substitute for x in the second equation using the first equation.
.. (6 +12y) +y = 214
.. 13y = 208 . . . . . . . . simplify and subtract 6
.. y = 16 . . . . . . . . . . . divide by 13
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The numbers are 198 and 16.

_____
These are solved easily any of several ways on a graphing calculator. You should learn to use yours for that purpose.
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