y2-y1 =M(x2-x1)
Ok Sir, you gave points : (2,1) and (3,4)
4-1/3-2 = 3
Ok we know our slope is 3, now pick any of the two points, and make an equation for this line, so lets go ahead and pick #1, (2,1)
Formula is same as before
y-1=3x-6
y=3x-5
I think its correct, pick as brainless sir, thanks.
They are the same slope
they are negative inversees (they multily to get -1)
2
-1/2
use the square viewer (on TI)
The relationship between the slopes of two lines that are parallel is they are the same.
The relationship between the slopes of two lines that are perpendicular is they are negative inverses of each other (they multiply to -1).
A line that is parallel to a line whose slope is 2 has slope 2.
A line that is perpendicular to a line whose slope is 2 has slope -1/2.
What must be done to make the graphs of two perpendicular lines appear
to intersect at right angles when they are graphed using a graphing
utility?
F(x)=-4x-1 if you sub 3 into it you get 3(-4)-1 which is -13 and 2x+4=10
There are many ways, but here is one:
x = 100
Since ‘x’ is 100 and we want 100 more, we just need to add ‘x’ to 623
Answer: x + 623 (Make sure you define your ‘x’ value)
Answer:
g (f (-3)) = -9
Step-by-step explanation:
Given:
Graphs of f(x) and g(x) are given
From the given graphs:
Finding g ( f (-3) ):
-----> g ( f (-3) )
-----> g(5)
-----> -9
so,
g ( f (-3) ) = -9
