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son4ous [18]
3 years ago
10

Convert the fraction 1/40 to a decimal form​

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
8 0

Answer:0.025

Step-by-step explanation:

AnnyKZ [126]3 years ago
5 0
Answer: 0.025

1 divided by 40 = 0.026

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24 : 8 = 3 : ?<br>7 : 35 = ? : 5<br>in detail please
Simora [160]
24 : 8 = 3 : 1 because 24 divided by 8 = 3 so
3 = 1

7 : 35 = 1 : 5 because 35 divided by 7 is 5 so
5 = 1
8 0
3 years ago
Order the numbers from least to greatest.<br> 17.2.3
nordsb [41]
The order of these numbers is 2, to 3, to 17. hope this helps :))
5 0
3 years ago
The probability that a lab specimen contains high levels of contamination is 0.10. A group of 4 independent samples are checked.
galben [10]

Answer:

a) 0.6561

b) 0.2916

c) 0.3439    

Step-by-step explanation:

We are given the following information:

Let us treat high level of contamination as our success.

p = P(High level of contamination) = P(success) = 0.10

n = 4

The, by binomial distribution:

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}\\\text{where x is the number of success}

a) P(No high level of contamination)

We put x = 0, in the formula.

P(X=0) = \binom{4}{0}.(0.10)^0.(1-0.10)^{4} =0.6561

Probability that no lab specimen contain high level of contamination is 0.6561

b) P(Exactly one high level of contamination)

We put x = 1, in the formula.

P(X=1) = \binom{4}{1}.(0.10)^1.(1-0.10)^{3} =0.2916

Probability that no lab specimen contain high level of contamination is 0.6561

c) P(At least one contains high level of contamination)

p(x \geq 1) = 1 - p( x = 0) = 1 - 0.6561 = 0.3439

Probability that at least 1 lab specimen contain high level of contamination is 0.3439

8 0
3 years ago
H(x)=x-1 is a factor of f(x)=x^5+1. Please select the best answer from the choices provided.
Zanzabum

Answer:true

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If 6 pipes fill a tank in 120 minutes, then 5 pipes can fill it in how many minutes​
Marianna [84]

Answer:

<u>It'll</u><u> </u><u>take</u><u> </u><u>1</u><u>4</u><u>4</u><u> </u><u>minutes</u><u> </u><u>for</u><u> </u><u>5</u><u> </u><u>pipes</u><u>.</u>

Step-by-step explanation:

{ \sf{6 \: pipes = 120 \: mins}} \\ { \sf{5 \: pipes = ( \frac{6}{5}  \times 120) \: mins}} \\  \\  = { \sf{144 \: mins}}

but practically, it seems to be abnormal. if 6 pipes take 120 mins, 5 pipes must takes a time greater than 120 mins cause amount of water flowing to the tank is decreasing.

<em>B</em><em>u</em><em>t</em><em> </em><em>t</em><em>h</em><em>e</em><em>r</em><em>e</em><em> </em><em>i</em><em>s</em><em> </em><em>a</em><em> </em><em>p</em><em>o</em><em>s</em><em>s</em><em>i</em><em>b</em><em>i</em><em>l</em><em>i</em><em>t</em><em>y</em><em> </em><em>t</em><em>h</em><em>a</em><em>t</em><em> </em><em>p</em><em>r</em><em>e</em><em>s</em><em>s</em><em>u</em><em>r</em><em>e</em><em> </em><em>o</em><em>f</em><em> </em><em>w</em><em>a</em><em>t</em><em>e</em><em>r</em><em> </em><em>w</em><em>a</em><em>s</em><em> </em><em>i</em><em>n</em><em>c</em><em>r</em><em>e</em><em>a</em><em>s</em><em>e</em><em>d</em><em> </em><em>f</em><em>o</em><em>r</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>c</em><em>a</em><em>s</em><em>e</em><em> </em><em>o</em><em>f</em><em> </em><em>f</em><em>i</em><em>v</em><em>e</em><em> </em><em>p</em><em>i</em><em>p</em><em>e</em><em>s</em><em>,</em><em> </em><em>t</em><em>h</em><em>a</em><em>t</em><em>'</em><em>s</em><em> </em><em>w</em><em>h</em><em>y</em><em> </em><em>i</em><em>t</em><em> </em><em>t</em><em>a</em><em>k</em><em>e</em><em>s</em><em> </em><em>a</em><em> </em><em>t</em><em>i</em><em>m</em><em>e</em><em> </em><em>l</em><em>e</em><em>s</em><em>s</em><em> </em><em>t</em><em>h</em><em>a</em><em>n</em><em> </em><em>1</em><em>2</em><em>0</em><em> </em><em>m</em><em>i</em><em>n</em><em>s</em><em>.</em><em> </em><em>(</em><em>t</em><em> </em><em><</em><em> </em><em>1</em><em>2</em><em>0</em><em>)</em>

5 0
3 years ago
Read 2 more answers
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