7+11v=9v-9 how do you solve by steps
1 answer:
You're solving this equation for the variable 'v', so the main goal is to isolate it on one side of the equation.
7 + 11v = 9v - 9 Subtract 7 from both sides
7 - 7 + 11v = 9v - 9 - 7 Simplify
11v = 9v - 16 Subtract 9v from both sides
11v - 9v = 9v - 9v - 16 Simplify
2v = -16 Divide both sides by 2
= -
Simplify
v = -8
Check your answer by plugging the value (-8) into the original equation.
7 + 11(-8) = 9(-8) - 9 Simplify the mulitiplication steps
7 + (-88) = -72 - 9 Rewrite 7 + (-88) as 7 - 88
7 - 88 = -72 - 9 Simplify both sides
-81 = -81
The check worked out, so your answer is v = -8 .
7 + 11v = 9v - 9 Subtract 7 from both sides
7 - 7 + 11v = 9v - 9 - 7 Simplify
11v = 9v - 16 Subtract 9v from both sides
11v - 9v = 9v - 9v - 16 Simplify
2v = -16 Divide both sides by 2
v = -8
Check your answer by plugging the value (-8) into the original equation.
7 + 11(-8) = 9(-8) - 9 Simplify the mulitiplication steps
7 + (-88) = -72 - 9 Rewrite 7 + (-88) as 7 - 88
7 - 88 = -72 - 9 Simplify both sides
-81 = -81
The check worked out, so your answer is v = -8 .
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Answer:
The co-ordinates of Q' is (5,2).
Step-by-step explanation:
Given:
Pre-image point
Q(-7,-6)
To find Image point Q' after following translation.
Solution:
Translation rules:
Horizontal shift:
when the point is translated
units to the right.
when the point is translated
units to the left.
Vertical shift:
when the point is translated
units up.
when the point is translated
units down.
Given translation shows the point is shifted 12 units to the right and 8 units up.
The point Q' can be given as:
Q'=
So, the co-ordinates of Q' is (5,2). (Answer)