Question

The bases on a baseball diamond are 90 feet apart. how far is it from home plate to second base?

Answer 1

See diagram

so we got a right triangle

so for a right triangle, when we've got legs a and b and hytponuse c then
a²+b²=c²


so the legs are 90 and 90
hytponuse is distance from home to 2nd

so
90²+90²=c²
8100+8100²=c²
16200=c²
sqrt both sides
90√2=c
aprox
127.279ft
about 127ft

Answer 2

Assuming that the bases are all within right angles of each other:
Form a triangle with vertices at home base, first, and second. Home to first is 90ft and first to second is also 90ft.
Use the formula a^2+b^2=c^2 to find the the missing length.
90^2+90^2=c^2
8100+8100=c^2
16200=c^2
Sqrt(16200)=c
c=127.279