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Crazy boy [7]
3 years ago
9

The point A(–1, 4) is translated five units right and three units down. Which rule describes the translation?

Mathematics
2 answers:
Gnom [1K]3 years ago
6 0

ur answer is B Step-by-step explanation:

I said so just do it

mafiozo [28]3 years ago
6 0

its b. that is the answer.

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There are three grades in the school. One grade has 1/3 of the students, one grade has 1/4 of the students. What fraction of stu
AlladinOne [14]

Answer:

Step-by-step explanation:

Let x represent the total number of stdents that has all grades in the school.

There are three grades in the school. One grade has 1/3 of the students, this means that number of students that belongs tho this grade is 1/3 × x = x/3

One grade has 1/4 of the students, this means that number of students that belongs to this grade is 1/4 × x = x/4

Total number of students in both grades would be x/3 +/x/4 = 7x/12

The number of students in the remaining grade would be

x - 7x/12 = 5x/12

fraction of students in the remaining grade would be

(5x/12)/x = 5/12

4 0
3 years ago
GIVING BRAILEST<br> Describe a situation that the equation could represent g+3<br> _____ =15<br> 6
krek1111 [17]

Answer:

g=153

Step-by-step explanation:

i hope this helped...

6 0
3 years ago
The product of two consecutive room numbers is 420. find the room numbers.
marissa [1.9K]
Hello : 
the  consecutive room numbers are : n , n+1
n(n+1) =420
n²+n -420 = 0 
the discriminant delta = b² - 4ac       ( a = 1  and b =  1  and   c = - 420
delta = (1)²-4(1)(-420) =1681= 41²
n = (-1 -41)/2    ( refused negatif number)
or 
n = (-1+41)/2 =20
<span> the room numbers.are : 20  , 21</span>
7 0
3 years ago
Read 2 more answers
G varies directly with h and inversely with the square off. When h=16,f=2,
Rufina [12.5K]

Answer:

wefew

Step-by-step explanation:

awhefiuLLLESoagFVRESESGREGESRGSAERG$W$EG$%agwafer

6 0
3 years ago
Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval for a
Vikki [24]

Answer:

0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730

0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890

And the confidence interval would be:

0.730 \leq \p \leq 0.890

Step-by-step explanation:

Information given:

n=131 represent the sample size

\hat p=0.81 represent the estimated proportion

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.326

And replacing into the confidence interval formula we got:

0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730

0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890

And the confidence interval would be:

0.730 \leq \p \leq 0.890

6 0
3 years ago
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