The lengths of HJ and JK are 50 and 72 respectively.
Given: J is between H and K. the length of HJ=2x+4, JK=3x+3, and HK=22.
The line HJ and JK are collinear then the total length is given as: HJ+JK=HK
substitute values
⇒ (2x+4)+(3x+3)=22
⇒ 5x+7=22
⇒ 5x=22-7
⇒ 5x=15
⇒ x=3
Thus, the length of HJ is (2x+4)=(2*3+4)=10
And the length of JK is (3x+3)=(3*3+3)=12
Learn more about collinear lines here: brainly.com/question/27943430
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Answer:
2
Step-by-step explanation:
We have two points so we can find the slope
m = ( y2-y1)/(x2-x1)
= ( -11 - -1)/( 4 -9)
= (-11+1)/( 4-9)
-10/ -5
= 2
Answer:
1: 39,284
2: 58,672.8
3: 2,066.79153912
4: 183.801664976
5: 8,744,119.16410
Those are the answers to the problems now you can just determine which ones are from least to greatest
Fidn volume
V=hpir^2
d/2=r
1.4/2=0.7=r
height=3.5
V=3.5*3.14*0.7^2
V=5.3851
1.5 times t=5.3851
divide both sides by 1.5
t=3.59
round
t=4
4 minutes
Answer:
Graphed this on desmos, hope it helped!!
Step-by-step explanation:
