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3 years ago

School 2x still sucks

Mathematics

2 answers:

Alexeev081 [22]3 years ago

6 0

This question was asked almost a year ago, there is a very good chance that they're not even in school anymore, it's crazy to think about. A year ago, I was hesitant on wearing a mask for the first couple of times and was starting to get used to the changes that were soon to come, while this guy was here, begging people for answers to a question so he could pass highschool. Now, he's probably living his best life right now and doesn't even know what I'm typing right now, either that, or he's working at McDonald's. Honestly though, time flies by so fast though, it really is crazy.

garik1379 [7]3 years ago

5 0

Answer: 1

Explanation:

$1\frac{3}{5} = \frac{8}{5}$

$\frac{8}{5} * \frac{5}{8} = \frac{40}{40}$

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Step-by-step explanation:

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3 years ago

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4 years ago

Please help me with the below question.

tresset_1 [31]

We have the following three conclusions about the <em>piecewise</em> function evaluated at x = 14.75:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
$\lim_{t \to 14.75^{+}} f(t) = 10$ .
$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

<h3>How to determinate the limit in a piecewise function</h3>

In a <em>piecewise</em> function, the limit for a given value exists when the two <em>lateral</em> limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.

According to the definition of <em>lateral</em> limit and by observing carefully the figure, we have the following conclusions:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
$\lim_{t \to 14.75^{+}} f(t) = 10$ .
$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

To learn more on piecewise function: brainly.com/question/12561612

#SPJ1

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2 years ago