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3 years ago

The ratio of boys to girls in a class is 3:4. There are 35 students in the class. How many students are boys?

Mathematics

1 answer:

cricket20 [7]3 years ago

6 0

Answer:

15 boys and 20 girls

Step-by-step explanation:

1. Since we cant simplify 3:4 we will leave it just like that.

2. 3x+4x=35

3. We add them both to give us 7x=35

4. We divide by 7 to get x by itself which results in 35/7=5.

x=5

5. Now we found x we can create 2 seperate soulutions:

3(5)=

and 4(5)=

Therefore there are 15 boys and 20 girls in the class. This makes sense because 15/20 reduced is 3 over 4.

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oksian1 [2.3K]

Answer:

Step-by-step explanation:

Given the simultaneous equation;

$\frac{a}{b} - \frac{b}{2} = 10\\a - b = 29$

From 2;

a = 29 + b ....3

Substitute 3 into 1;

$\frac{29+b}{b} - \frac{b}{2} = 10\\\frac{2(29+b)-b^2}{2b} = 10\\\frac{58+2b-b^2}{2b} = 10\\58+2b-b^2 = 20b\\b^2-2b-58 = -20b\\b^2-2b+20b -58 = 0\\b^2+18b-58 = 0\\$

Factorize

b = -18±√18²-4(-58)/2

b = -18±√324+232/2

b = -18±√556/2

b = -18±23.58/2

b = -18-23.58/2 and -18+23.58/2

b = -41.58/2 and 5.58/2

b = -20.79 and 2.79

Since a = 29 + b

when b = -20.79

a = 29 - 20.79

a = 8.21

<em>Hence the solution to the system of equation is (8.21, -20.79)</em>

7 0

3 years ago

-3(_x + 4) = 9x – 12 Using the distributive property, what number would go in the blank in order for the given statement to be c

Licemer1 [7]

Answer:

-3(-3x + 4) = 9x - 12

Step-by-step explanation:

-3( Ax + 4) = 9x - 12

-3Ax -12 = 9x - 12

Equating coefficients of x terms on both sides :

-3A = 9

A = -3

Therefore, -3(-3x + 4) = 9x - 12

4 0

3 years ago

Plz help for this answer

aleksandr82 [10.1K]

Answer:

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Step-by-step explanation:

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3 years ago

A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess

statuscvo [17]

Let's start by visualising this concept.

Number of grains on square:
1 2 4 8 16 ...

We can see that it starts to form a geometric sequence, with the common ratio being 2.

For the first question, we simply want the fifteenth term, so we just use the nth term geometric form:
$T_n = ar^{n - 1}$
$T_{15} = 2^{14} = 16384$

Thus, there are 16, 384 grains on the fifteenth square.

The second question begs the same process, only this time, it's a summation. Using our sum to n terms of geometric sequence, we get:
$S_n = \frac{a(r^{n} - 1)}{r - 1}$
$S_{15} = \frac{2^{15} - 1}{2 - 1}$
$S_{15} = 2^{15} - 1 = 32767$

Thus, there are 32, 767 total grains on the first 15 squares, and you should be able to work the rest from here.

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago