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Roman55 [17]
3 years ago
10

Identify the coordinates of the vertices of the polygon.

Mathematics
1 answer:
Norma-Jean [14]3 years ago
4 0

no sé la verdad cual es. hay más gente que te pueda ayudar con esa respuesta, disculpa la verdad

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2010 0.15
aniked [119]

Answer:

it is a :) hope this helped :)

Step-by-step explanation:

4 0
3 years ago
Which shows the ratio 16 : 100 as a fraction in simplified form?
Alika [10]

Answer:

16 : 100 = 8 : 50 = 4 : 25

Step-by-step explanation:

You just half each side by the same number

7 0
3 years ago
What is the distance bewteen -7 and 41
Gala2k [10]
To find distance, subtract the largest number from smaller

41 - (-7)

41 + 7 = 48

the distance is 48

hope this helps
3 0
3 years ago
Given that sin theta = 1/4, 0→theta→π/2, what<br>. what is the exact value of cos 8?​
natali 33 [55]
<h3>Answer: Choice B \frac{\sqrt{15}}{4}</h3>

===========================================================

Work Shown:

Angle theta is between 0 and pi/2, so this angle is in quadrant Q1.

Square both sides of the given equation

\sin \theta = \frac{1}{4}\\\\\sin^2 \theta = \left(\frac{1}{4}\right)^2\\\\\sin^2 \theta = \frac{1}{16}

Then use the pythagorean trig identity to get

\sin^2 \theta + \cos^2 \theta = 1\\\\\cos^2 \theta = 1-\sin^2 \theta\\\\\cos \theta = \sqrt{1-\sin^2 \theta} \ \ \ \text{cosine is positive in Q1}\\\\\cos \theta = \sqrt{1-\frac{1}{16}}\\\\\cos \theta = \sqrt{\frac{16}{16}-\frac{1}{16}}\\\\\cos \theta = \sqrt{\frac{16-1}{16}}\\\\\cos \theta = \sqrt{\frac{15}{16}}\\\\\cos \theta = \frac{\sqrt{15}}{\sqrt{16}}\\\\\cos \theta = \frac{\sqrt{15}}{4}\\\\

3 0
3 years ago
A liquid storage container is being filled at a constant rate. The container is being filled at a rate of 1/3 gallon per 1/4 min
denpristay [2]
1/4 x 16 = 4 min
 so 
1/3 x 16 = 16/3
8 0
3 years ago
Read 2 more answers
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