Que expresión representa el teorema de Pitágoras

I need help what goes in the box I need help ASAP ..

Reika [66]

Answer:

ion kno

Step-by-step explanation:

6 0

3 years ago

Roll a pair of dice until it lands doubles.What is the probability you will get the first doubles within three rolls? (Correct t

mr Goodwill [35]

Answer:

Probability of rolling doubles in first three roles = 0.4124

Probability of it taking between 5 to 7 rolls = 0.1988

Step-by-step explanation:

Let's start by the total number of possible outcomes. This is 6 for one dice, and 6 for the other. So in total that's 6 x 6 = 36 different outcomes of the dice roll.

The number of ways we can roll a double is 6.

So the probability of rolling a double would be the number of ways to roll a double divided by the total possible outcomes.

This is : $\frac{6}{36}$ = 0.1667

The probability of NOT rolling a double: 1 - 0.1667 = 0.8333

Since the probability of rolling a double is equal to 1 - probability of not rolling a double, we can answer the first question in the following way.

The probability of NOT rolling a double for the first THREE turns: 0.8333 x 0.8333 x 0.8333 = 0.5786

Probability of rolling a double in first THREE turns: 1 - 0.5786 = 0.4124

The probability it will take between 5 to 7 rolls would be:

EQUATION 1: (probability of rolling no doubles in first 4 turns) x (probability of rolling a double in the next three turns)

Since we have already found the probability of rolling a double in three turns to be 0.4124, all we need to find is the probability of NOT rolling a double in the first four turns.

This is: 0.8333 * 0.8333 * 0.8333 * 0.8333 = 0.4822

Plugging this into EQUATION 1 we get: 0.4822 * 0.4124 = 0.1988

5 0

3 years ago

The coordinates for the vertices of a right triangle are (1, 4), (6, 4), and (6,1). What is the length of the longer leg? A) 3 B

Semmy [17]

Let
A------> (1, 4)
B------> (6, 4)
C-----> (6,1)

we know that
In a right triangle there are two legs and one hypotenuse

step 1
find the distance AB
d=√[(y2-y1)²+(x2-x1)²]------> d=√[(4-4)²+(6-1)²]-----> d=√25----> 5
AB=5 units

step 2
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> d=√[(1-4)²+(6-6)²]-----> d=√9----> 3
BC=3 units

step 3
find the distance AC
d=√[(y2-y1)²+(x2-x1)²]------> d=√[(1-4)²+(6-1)²]-----> d=√34----> 5.83
AC=5.83 units

therefore
the two legs are
AB=5 units
BC=3 units
the hypotenuse is
AC=5.83 units

the answer is
the length of the longer leg is AB=5 units

see the attached figure