Answer:
a) P(X∩Y) = 0.2
b) 
= 0.16
c) P = 0.47
Step-by-step explanation:
Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.
So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67
Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:
P(X∩Y) = P(X) + P(Y) - P(X∪Y)
P(X∩Y) = 0.36 + 0.51 - 0.67
P(X∩Y) = 0.2
On the other hand, the probability that he must stop at the first signal but not at the second one can be calculated as:
= P(X) - P(X∩Y)
= 0.36 - 0.2 = 0.16
At the same way, the probability 
that he must stop at the second signal but not at the first one can be calculated as:
= P(Y) - P(X∩Y)
= 0.51 - 0.2 = 0.31
So, the probability that he must stop at exactly one signal is:
Hello :
3x3 – 11x2 – 26x + 30 divided by x – 5 is :<span>3x2 + 4x – 6
because :
(x-5)(3x²+4x-6)=3x^3+4x²-6x-15x²-20x+30 =</span>3x3 – 11x2 – 26x + 30
The pentagon has a sum of interior angles of 540 degrees.
Therefore,
(4x + 5) + (5x - 5) + (6x + 10) + (4x + 10) + 7x = 540;
26x = 520;
x = 20;
Answer: I found the answer of A=9h
