The coordinates for the vertices of a right triangle are (1, 4), (6, 4), and (6,1). What is the length of the longer leg? A) 3 B
) 4 C) 5 D) 6
2 answers:
Let
A------> <span>(1, 4)
B------> (6, 4)
C-----> (6,1)
we know that
In </span><span>a right triangle there are two legs and one hypotenuse
</span><span>
step 1
find the distance AB
d=</span>√[(y2-y1)²+(x2-x1)²]------> d=√[(4-4)²+(6-1)²]-----> d=√25----> 5
AB=5 units
step 2
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> d=√[(1-4)²+(6-6)²]-----> d=√9----> 3
BC=3 units
step 3
find the distance AC
d=√[(y2-y1)²+(x2-x1)²]------> d=√[(1-4)²+(6-1)²]-----> d=√34----> 5.83
AC=5.83 units
therefore
the two legs are
AB=5 units
BC=3 units
the hypotenuse is
AC=5.83 units
the answer is
<span>the length of the longer leg is AB=5 units
</span>
see the attached figure
A------> <span>(1, 4)
B------> (6, 4)
C-----> (6,1)
we know that
In </span><span>a right triangle there are two legs and one hypotenuse
</span><span>
step 1
find the distance AB
d=</span>√[(y2-y1)²+(x2-x1)²]------> d=√[(4-4)²+(6-1)²]-----> d=√25----> 5
AB=5 units
step 2
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> d=√[(1-4)²+(6-6)²]-----> d=√9----> 3
BC=3 units
step 3
find the distance AC
d=√[(y2-y1)²+(x2-x1)²]------> d=√[(1-4)²+(6-1)²]-----> d=√34----> 5.83
AC=5.83 units
therefore
the two legs are
AB=5 units
BC=3 units
the hypotenuse is
AC=5.83 units
the answer is
<span>the length of the longer leg is AB=5 units
</span>
see the attached figure
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Greetings from Brasil...
Let's apply the given formula:
A = (1/2)·B·H
The base of this polygon (in this case, the triangle) is B
B = X² - 2X + 6
The height of this polygon is H and is H
H = X + 4
Applying these values (B and H) in the given formula.....
A = (1/2)·B·H
A = (1/2)·(X² - 2X + 6)·(X + 4)
A = (1/2)·(X³ + 2X² - 2X + 24)
A = (X³/2) + X² - X + 12
OR
A = (X³ + 2X² - 2X + 24)/2
Answer:
f(x)=8x-25
Step-by-step explanation:
