Answer:
Distance around the pool = 162.8 feet
Area of the pool = 957 square feet
Step-by-step explanation:
Distance around the swimming pool = Perimeter of the pool
Perimeter of the pool which is a composite figure will be,
= Circumference of the semicircle + Sum of three sides of the pool
= πr + 2×(length of the pool) + width of the pool
= 3.14×(10) + 2×40 + 20
= 62.8 + 80 + 20
= 162.8 ft
Area of the pool = Area of the semicircle + Area of the rectangular pool
= 
= 
= 157 + 800
= 957 square feet
You have to find first the discriminant
∆=8^2-4*(-1) *(-7) =36
x=(-8±√36) /-2=(-8±6)/-2=4±3=1 or 7
So x(1)=1 or x(2)=7
-x^2+8x-7=[x-x(1) ][x-x(2) ]=(x-1) (x-7)
<h3>
Answer: shaded region has area 107 square feet</h3>
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Work Shown:
A = area of larger rectangle
A = length*width = 9*15 = 135 square feet
B = area of smaller rectangle
B = length*width = 7*4 = 28 square feet
C = area of shaded region
C = difference in areas of A and B
C = A - B = 135 - 28 = 107 square feet
Answer:
Step-by-step explanation:
Converse
Answer:
Option (2)
Step-by-step explanation:
Measure of angle formed by two tangents from a point outside the circleis half the difference of the measures of the intercepted arcs.
From the figure attached,
m∠C = ![\frac{1}{2}[m(\text{major arc AB})-m(\text{minor arc AB)}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Bm%28%5Ctext%7Bmajor%20arc%20AB%7D%29-m%28%5Ctext%7Bminor%20arc%20AB%29%7D%5D)
= ![\frac{1}{2}[(360-m\widehat{AB})-m(\widehat{AB})]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%28360-m%5Cwidehat%7BAB%7D%29-m%28%5Cwidehat%7BAB%7D%29%5D)
= ![\frac{1}{2}[360-2m(\widehat{AB})]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B360-2m%28%5Cwidehat%7BAB%7D%29%5D)
= 
= 180 - 150
= 30°
Therefore, measure of angle C will be 30°.
Option (2) is the answer.
