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2 years ago

Wht do i put in the square box ?

Mathematics

1 answer:

Brut [27]2 years ago

7 0

Answer:

3.75

Step-by-step explanation:

Volume = length x width x height

= 2.5 x 1 x 1.5

= 3.75 cm^3

WE count number of blocks for all values seperately, like

for height its three blocks and one block is equal to 1/2

so.

1/2 x 3= 1.5

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Natali5045456 [20]

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Step-by-step explanation:

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2 years ago

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3 years ago

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3 years ago

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What is d if <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3d-2%7D%7B8%7D%20%3D%20-d%2B16%5Cfrac%7B1%7D%7B4%7D" id="TexFormula1" t

Harlamova29_29 [7]

Answer: d=12

Step-by-step explanation:

$\displaystyle\\\frac{3d-2}{8} =-d+16\frac{1}{4} \\\\\frac{3d-2}{8} =-d+\frac{16*4+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{64+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{65}{4}$

Multiply both parts of the equation by 8:

$\displaystyle\\3d-2=(-d+\frac{65}{4} )(8)\\\\3d-2=-8d+65*2\\\\3d-2=-8d+130\\\\3d-2+2=-8d+130+2\\\\3d=-8d+132\\\\3d+8d=-8d+132+8d\\\\11d=132\\$

Divide both parts of the equation by 11:

$d=12$

8 0

1 year ago

A pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. The height, h, of th

Gennadij [26K]

<h2>Explanation:</h2>

In this problem we have a pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. So the height, h, of the pumpkin at time t seconds after the launch can be modeled by the equation:

$h(t) = -16t^2 + 84t + 20$

So this is the equation of a parabola. The maximum of this parabola occurs at its vertex. So let's find this vertex:

$\text{The x-value of the vertex is}: \\ \\ t=-\frac{b}{2a} \\ \\ \\ Where: \\ \\ a=-16 \\ \\ b=84 \\ \\ c=20 \\ \\ \\ t=-\frac{84}{2(-16)} \\ \\ t=-\frac{84}{-32} \\ \\ t=\frac{21}{8}=2.625 \\ \\ h(2.625)=-16(2.625)^2+84(2.625)+20 \\ \\ h(2.625)=-110.25+220.5+20 \\ \\ h(2.625)=130.25m$

Finally, the maximum occurs at time 2.625 seconds when the height is 130.25m

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3 years ago