<span>2n−1 + 7n - 2
= 9n - 3
-------------------</span>
Since TSQ and QSR are supplementary, they give 180 when summed. TSQ is 150, so QSR must be 30.
Therefore, you have

16.22 divided by 2 = your answer. (8.11)
There are 7 keys in each octave (C,D,E,F,G,A and B) so it would make sense to divide 52 to 7.
52/7=7 octaves and 3 extra kets