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polet [3.4K]
3 years ago
10

2(4K + 7) Helppp lol

Mathematics
2 answers:
Hoochie [10]3 years ago
8 0
8k+14

Hope this helps !!!
arlik [135]3 years ago
8 0

Answer:

8k + 14

Step-by-step explanation:

2(4K + 7)

8k + 14

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Find the complex zeros of x^3+27. write f in factored form
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x^3+27=0
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\\x^2-3x+9=0
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\\
\\x_{1,2}= \frac{-b\pm \sqrt{b^2-4ac} }{2a} = \frac{-(-3)\pm \sqrt{(-3)^2-4\times1\times9} }{2\times1} =\frac{3\pm \sqrt{-27} }{2} =\frac{3\pm 3\sqrt{3}i }{2} 
\\
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