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lianna [129]
3 years ago
15

2hr 57min+3hrs42min​

Mathematics
2 answers:
Mademuasel [1]3 years ago
6 0

Answer:

6hr 39 min

Step-by-step explanation:

Add both

2hr 57 min

<u>+ 3hr 42 </u><u>min </u>

<u> </u><u> </u><u>5</u><u>h</u><u>r </u><u>9</u><u>9</u><u> </u><u>min </u>

we know that 1 hr = 60 min

then , 99 min = 1hr 39 min

so, 5hr + 1hr 39min

= 6hr 39 min

Ber [7]3 years ago
4 0

Answer:

6 hrs 33 minutes

Step-by-step explanation:

 2hr 57min

+3hrs42min​

----------------------

5 hrs 99 minutes

But 1 hr = 60 minutes so subtract 60 minutes and add 1 hour

6 hrs 33 minutes

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A man gets an invoice for ​$460 with terms 4/10, ​1/15, n/30. How much would he pay 6 days after the invoice​ date?
7nadin3 [17]

Answer:

$441.60

Step-by-step explanation:

Invoice amount: $460

Term 4/10= 4% discount if paid early within the first 10 days of the invoice date

Amount due: $441.60

Discount amount: $18.40

Invoice amount: $460

Term: 1/15= 1% discount if paid early within the first 15 days of the invoice date

Amount due: $455.40

Discount amount: $4.60

Invoice amount: $460

Term: n/30= no discount if paid on or after the 30 days from the invoice date

Amount due: $460

Discount amount: $0

3 0
2 years ago
Two children own two-way radios that have a maximum range of 3 miles. One leaves a certain point at 1:00 P.M., walking due north
Grace [21]

Answer:

The answer is 21 minutes

Step-by-step explanation:

We use the equation Xf = Xo + vt

1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])

2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]

  • x_{1f1} =x_{o} +v_{1} t_{1} \\x_{1f1} =0+.1(15)\\x_{1f1} =1.5 [mi]

3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]

  • Child 1 final position => x_{1f} = x_{1f1} +v_{1} t\\x_{1f} =1.5+v_{1} t
  • Child 2 final position => x_{2f} =0+v_{2} t

4) Sum the equations and equate to 3

  • x_{1f} +x_{2f} =3

5) Substitute the values we already know

  • 1.5+v_{1} t+v_{2}t=3\\ 1.5+.1t+.15t=3\\1.5+.25t=3\\t=\frac{3-1.5}{.25} \\t=6 [min]

6) in 15 + 6 minutes they will be 3miles apart

7) In 21 minutes they will still be able to communicate with one another.

7 0
3 years ago
On a 8.5 x 11 inches (or larger) paper, create a carnival game (for example it could be: throwing a dart at a target, ball throu
Keith_Richards [23]

The probability of winning the game is 0.065

<h3>The description of the game</h3>

The game involves throwing two darts at two targets.

To win the game, the darts must hit anywhere in the following shapes

  • Rectangle: 5 by 4 inches
  • Circle: Radius, r = 3 inches

<h3>The probability of winning</h3>

The area of the paper is:

Area = 8.5 inches * 11 inches

Area = 93.5 square inches

The area of the rectangle on the paper is:

Area = 5 inches * 4 inches

Area = 20 square inches

The area of the circle on the paper is:

Area = π * (3 inches)²

Area = 28.3 square inches

The probability of landing on both shapes is

P(Both) = 20/93.5 * 28.3/93.5

Evaluate

P(Both) = 0.065

Hence, the probability of winning the game is 0.065

Read more about probability at:

brainly.com/question/24756209

#SPJ1

7 0
2 years ago
What is 1/6d+2/3 = 1/4(d-2)
GenaCL600 [577]
1/6d + 2/3 = 1/4(d - 2)

First, simplify \frac{1}{6} d to \frac{d}{6} / Your problem should look like: \frac{d}{6} + \frac{2}{3} = \frac{1}{4} (d - 2)
Second, simplify \frac{1}{4} (d - 2) to \frac{d-2}{4} / Your problem should look like: \frac{d}{6} + \frac{2}{3} = \frac{d-2}{4}
Third, multiply both sides by 12 (the LCM of 6,4) / Your problem should look like: 2d + 8 = 3(d - 2)
Fourth, expand. / Your problem should look like: 2d + 8 = 3d - 6
Fifth, subtract 2d from both sides. / Your problem should look like: 8 = 3d - 6 - 2d
Sixth, simplify 3d - 6 - 2d to d - 6 / Your problem should look like: 8 = d - 6
Seventh,add 6 to both sides. / Your problem should look like: 8 + 6 = d
Eighth, simplify 8 + 6 to 14 / Your problem should look like:14 = d
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Answer: d = 14

3 0
3 years ago
An acute angle can have all of the following measures except 89 45 10 0
Naddik [55]
0 is the only degree that cannot work
3 0
3 years ago
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