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Norma-Jean [14]
3 years ago
6

On a coordinate plane, a line is drawn from point A to point B. Point A is at (2, negative 3) and point B is at (negative 4, 9).

What are the x- and y- coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2? x = (StartFraction m Over m + n EndFraction) (x 2 minus x 1) + x 1 y = (StartFraction m Over m + n EndFraction) (y 2 minus y 1) + y 1 (0, 1) (–1, 3) (–2, 5) (1, 0)
Mathematics
2 answers:
zimovet [89]3 years ago
3 0

Answer: (0,1)

Step-by-step explanation:

If (x_1, y_1) and  (x_2, y_2) are two point son a coordinate plane and (x,y) dividing it in a ratio of m: n.

Then , the coordinates of (x,y) is given by :-

x=\dfrac{nx_1+mx_2}{m+n}

y=\dfrac{ny_1+my_2}{m+n}

Given : On a coordinate plane, a line is drawn from point A to point B. Point A is at (2, - 3) and point B is at (- 4, 9).

Then , the x- and y- coordinates of point E, which partitions the directed line segment from A to B into a ratio of 1:2 :

x=\dfrac{2(2)+1(-4)}{1+2}=0

y=\dfrac{2(-3)+1(9)}{1+2=1}

Hence, the x- and y- coordinates of point E = (0,1)

Vesna [10]3 years ago
3 0

Answer:

(0,1)

Step-by-step explanation: Correct on Edge

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The correct answer is:  [D]:  "17" .
______________________________________________________
The radius is:  " 17" .
______________________________________________________
Note:
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The formula/equation for the graph of a circle is:
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in which:  

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We are given the following equation of the graph of a particular circle:
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          →  (x − 4)²  +  (y + 12)² =  17² ;

which is in the correct form:

→  " (x − h)²  +  (y − k)² =  r²  " ;

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          →  { Note that: "k = NEGATIVE  12" } ;

→  Since the equation <u>for this particular circle</u> contains the expression:             _________________________________________________________    
                      →     "...(y + k)² ..." ;  
         
[as opposed to the standard form:  "...(y − k)² ..." ] ; 
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→  And since the coordinates of the center of a circle are represented by:
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→  And since:  " k = -12 " ;  (<u>for this particular circle</u>) ;
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then: 

 " [y − k ] ²  =  [ y − (k) ] ²  =  " [ y − (-12) ] ² " ;
                                    
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{NOTE:  Since:  "subtracting a negative" is the same as "adding a positive" ;

           →   So;  " [ y − (-12 ] " = " [ y + (⁺ 12) ] " = " (y + 12) "
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