Could someone plz just answer this now?
1 answer:
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Answer:
<em>x = 3 and y = 0</em>
Step-by-step explanation:
3y+x=3
-2y+5x=15
Isolate y in 3y + x = 3 :
Substitute in -2y + 5x = 15 :
Simplify the equation :
Isolate x in :
Proving x = 3
Isolate y in :
Proving y = 0
Your solved system of equations are x being 3, and y being 0.
Answer:
If whenever
f is <em>increasing</em> on I.
If whenever
f is <em>decreasing</em> on I.
Step-by-step explanation:
These are definitions for real-valued functions f:I→R. To help you remember the definitions, you can interpret them in the following way:
When you choose any two numbers on I and compare their image under f, the following can happen.
. Because x2 is bigger than x1, you can think of f also becoming bigger, that is, f is increasing. The bigger the number x2, the bigger f becomes.
. The bigger the number x2, the smaller f becomes so f is "going down", that is, f is decreasing.
Note that this must hold for ALL choices of x1, x2. There exist many functions that are neither increasing nor decreasing, but usually some definition applies for continuous functions on a small enough interval I.