Answer:
4 and 3 <------- That's the set I believe!
4(x -2) +(y +5) = 0 . . . . . an equation
4x +y = 3 . . . . . . . . . . . . the equation in standard form
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A graph can be seen at
https://www.desmos.com/calculator/3ct9gfxclj
Answer:
0.01
Step-by-step explanation:
Answer:
y = 2x + 1 --> linear
y = -4x + 7 --> non-linear
Not a solution for linear system.
Step-by-step explanation:
for (a), y = 2x+1, substitute the x and y values. keep in mind, that in a linear pair, (x, y). So, for the first equation you get:
7 = 2x3 + 1. This is correct, because 6 + 1 is 7. Therefore, (a) is linear.
for (b), we have to substitute our values again. You get:
7 = -4x3 + 7, which is
7 = -12+7, which is not true. So, (b) is not linear.
This means that for the linear pair (3, 7), it does not satisfy both equations, which means that it is not a solution for the linear system.
