Answer:
The zeros, -1.48 and 1.48, represent the times where the egg is on the ground.
Step-by-step explanation:
The roots, or zeros, of an expression are the x-intercepts. They are the points where the data crosses the x-axis. The y-coordinate at these points is 0. This means the height of the egg at these points is 0.
The values of a, b and c in this equation are -16, 0 and 35. Using the quadratic formula,
![x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\=\frac{-0\pm \sqrt{0^2-4(-16)(35)}}{2(-16)}\\\\=\frac{0\pm \sqrt{0--2240}}{-32}\\\\=\frac{0\pm \sqrt{2240}}{-32}\\\\=\frac{0\pm 47.33}{-32}\\\\=\frac{0+47.33}{-32}\text{ or }\frac{0-47.33}{-32}\\\\=\frac{47.33}{-32}\text{ or }\frac{-47.33}{32}\\\\=-1.48\text{ or }1.48](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D%5C%5C%5C%5C%3D%5Cfrac%7B-0%5Cpm%20%5Csqrt%7B0%5E2-4%28-16%29%2835%29%7D%7D%7B2%28-16%29%7D%5C%5C%5C%5C%3D%5Cfrac%7B0%5Cpm%20%5Csqrt%7B0--2240%7D%7D%7B-32%7D%5C%5C%5C%5C%3D%5Cfrac%7B0%5Cpm%20%5Csqrt%7B2240%7D%7D%7B-32%7D%5C%5C%5C%5C%3D%5Cfrac%7B0%5Cpm%2047.33%7D%7B-32%7D%5C%5C%5C%5C%3D%5Cfrac%7B0%2B47.33%7D%7B-32%7D%5Ctext%7B%20or%20%7D%5Cfrac%7B0-47.33%7D%7B-32%7D%5C%5C%5C%5C%3D%5Cfrac%7B47.33%7D%7B-32%7D%5Ctext%7B%20or%20%7D%5Cfrac%7B-47.33%7D%7B32%7D%5C%5C%5C%5C%3D-1.48%5Ctext%7B%20or%20%7D1.48)
Answer:
One solution
Step-by-step explanation:
10-8d=-10d
+8d +8d
10=-2d
/-2 /-2
-5=d
There is only one solution.
-hope it helps
Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
First you can convert 45 miles per hour to feet per hour:
45 × 5,280 = 237,600 feet per hour
Now you must remember that there are 60 minutes in an hour, and 60 seconds in a minute. So you can divide 237,600 feet per hour by 60 to get feet per minute:
237,600 ÷ 60 = 3,960 feet per minute
Now you just have to divide 3,960 by 60 again to get feet per second:
3,960 ÷ 60 = 66 feet per second
Now you know how fast the car can travel (in feet) in a second. So to work out how many feet it travels in 3 seconds, you just have to multiply 66 by 3:
66 × 3 = 198 feet
Therefore your final answer is <em>198 feet</em> :)
Answer:
An=9+2(n-1)
Step-by-step explanation:
Just learned this.
Its a arithmetic so it would always be a n-1 however it would be in parentheses after the common different.