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xenn [34]
3 years ago
11

Y = -2x^2 - 6 y = -(x-3)^2 + 8 solve the equation

Mathematics
1 answer:
Lady_Fox [76]3 years ago
6 0
I hope this helps you

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Find the measure of the angle indicated.<br> P<br> A) 92°<br> B) 61°<br> C 86°<br> D) 34°
cricket20 [7]

Answer:

92°÷^®√™÷√÷^π^π^^π^π°π°^÷

7 0
3 years ago
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A large dog weighs 80 pounds. What is the dog’s weight in ounces? (16 oz = 1 lb) A.5 oz B. 10 oz C. 640 oz D. 1,280 oz
Tema [17]

Answer:

1280 Oz - Option D

Step-by-step explanation:

16 ounces to a pound. 16 × 80 = 1280oz

8 0
3 years ago
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Weight gain during pregnancy. In 2004, the state of North Carolina released to the public a large data set containing informatio
Kryger [21]

Answer:

From the given data, there is not enough evidence to prove that there is a statistically significant difference between the two population means

Step-by-step explanation:

The number of younger moms, in the study = 837

The average weight gain of younger moms, \overline x₁ = 30.67 pounds

The standard deviation of the weight gain of younger moms, s₁ = 14.69 pounds

(30.67 - 28.52)/√((14.69^2)/837 + 13²/143))

The number of younger moms, in the study = 143

The average weight gain of mature moms, \overline x₂ = 28.52 pounds

The standard deviation of the weight gain of mature moms, s₂ = 13 pounds

The test statistic for the difference in two populations is given as follows;

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\dfrac{s_1^{2} }{n_{1}}-\dfrac{s _{2}^{2}}{n_{2}}}}

Therefore, we get;

t=\dfrac{(30.67-28.52)}{\sqrt{\dfrac{14.69^{2} }{837}-\dfrac{13^{2}}{143}}} \approx 1.7919

The test statistic ≈ (1.7919)

Using a graphing calculator, we get;

The critical-t = ±1.971379, p = 0.07459697

Therefore, given that the test statistic, (1.7919), < critical-t (0.07459697), we fail to reject the null hypothesis, therefor, the given data does not provide convincing evidence that there is a significant difference between the two population means

7 0
3 years ago
Temperature at 9:00PM was 15° By 5 AM the temperature had dropped 20° what was the temperature at 5 PM
Arisa [49]
From 9 P.M. to 5 A.M. the temperature dropped 20°, making the rate over 8 hours, -2.5° Per Hour. By 5 A.M., the temperature is -5° since we had to do 15 - 20. From 5 AM to 5 P.M. is 12 hours so -2.5 x 12 = -30 making 30 how much the temperature dropped between 5 A.M. to 5 P.M. Finally, our last equation is -5 - 30 making -35 our answer.
4 0
3 years ago
The radius of a clock face is 8.5 centimeters. What is the area of the clock face​
hodyreva [135]

Answer:

B

Step-by-step explanation:

When finding the area of a circle you have to use the formula

Area= Pie x radius^2

Radius=8.5

So you have to plug that into the equation.

8.5x8.5=72.25

72.25x3.14=226.87

So Area is 226.87

So your answer is B

4 0
4 years ago
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