Find the slope of the graph

A book falls from a shelf that is 5 feet above the floor. A model for the height h in feet if an object dropped from an initial

Brums [2.3K]

Answer:

About 0.559 seconds

Step-by-step explanation:

The height equation is:

$h=-16t^2+h_0$

Where $h_0$ is the initial height of the book, which is 5, so we can write:

$h=-16t^2+5$

Now, we want time it took for the book to reach ground (h = 0)

So, we substitute h = 0 and solve for t:

$h=-16t^2+5\\0=-16t^2+5\\16t^2=5\\t^2=0.3125\\t=0.5590\\t=0.559$

It took about 0.559 seconds for the book to reach the ground

5 0

3 years ago

the temperature outside was 50 during the day and fell 16 at night. What was the temperature at night?

mamaluj [8]

You subtract 16 from 50

so 50-16=34

so your answer is 34 degree

7 0

3 years ago

Read 2 more answers

HELP PLS!!! Solve the inequality $x^3 + 4x > 5x^2$.

rewona [7]

Answer:

de fk?

Step-by-step explanation:

wth is that

8 0

3 years ago

A survey of 700 adults from a certain region asked, "What do you buy from your mobile device?" The results indicated that 59%

Kryger [21]

Answer:

a) the test statistic z = 1.891

the null hypothesis accepted at 95% level of significance

b) the critical values of 95% level of significance is zα =1.96

c) 95% of confidence intervals are (0.523 ,0.596)

Step-by-step explanation:

A survey of 700 adults from a certain region

Given sample sizes $n_{1} = 400 and n_{2} = 300$

Proportion of mean $p_{1} = \frac{236}{400} = 0.59 and p_{2} = \frac{156}{300} = 0.52$

Null hypothesis H0 : assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

Alternative hypothesis H1:- p1 ≠ p2

a) The test statistic is

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }$

where $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

on calculation we get p = 0.56

now q =1-p = 1-0.56=0.44

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )} } }\\ =\frac{0.56-0.52}{\sqrt{0.56X0.44}(\frac{1}{400}+\frac{1}{300} }$

after calculation we get z = 1.891

b) The critical value at 95% confidence interval zα = 1.96 (from z-table)

The calculated z- value < the tabulated value

therefore the null hypothesis accepted

conclusion:-

assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

c) 95% confidence intervals

The confidence intervals are P± 1.96(√PQ/n)

we know that = $p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}$

after calculation we get P = 0.56 and Q =1-P =0.44

Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))

now substitute values , we get

( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))

on simplification we get (0.523 ,0.596)

Therefore the population proportion (0.56) lies in between the 95% of confidence intervals (0.523 ,0.596)

3 0

3 years ago

One can convert temperature from Fahrenheit into Newton using the formula N=11/60(F-32) . What is the temperature in Fahrenheit

Rasek [7]

We are given

$N=\frac{11}{60} (F-32)$

Since, we have to solve for F

so, we will isolate F on anyone side

step-1:

Multiply both sides by 60

$60\times N=60\times \frac{11}{60} (F-32)$

$60N=11 (F-32)$

step-2:

Divide both sides by 11

$\frac{60N}{11} =\frac{11(F-32)}{11}$

$\frac{60}{11}N =F-32$

step-3:

Add both sides by 32

$\frac{60}{11}N+32 =F-32+32$

$\frac{60}{11}N+32 =F$

so, we get

$F=\frac{60}{11}N+32$ ................Answer

5 0

2 years ago