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astra-53 [7]
3 years ago
6

Could someone please help me with this problem? I don't understand.

Mathematics
1 answer:
sasho [114]3 years ago
4 0
Try dividing 150 by 2 1/2 and your answer would be 6.25 you may want to double check that math though
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HELP PLS!!! ASAP
horrorfan [7]

Answer:

x(3 – 4)

Step-by-step explanation:

x^3y

/x^4y

get rid of y

x^3/x^4

subtract exponents

x(3 – 4)

Brainliest please ask me if you have more questions.

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prohojiy [21]
3 and 11 are the answers
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ivann1987 [24]

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(0,3)

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7 0
3 years ago
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olga nikolaevna [1]

\left\{\begin{array}{ccc}x+3y-z=2\\4x+2y+5z=1\\3x+z=12&\to z=12-3x\end{array}\right\\\\\text{substitute the value of z to the first and second equation}\\\\\left\{\begin{array}{ccc}x+3y-(12-3x)=2\\4x+2y+5(12-3x)=1\end{array}\right\\\\\left\{\begin{array}{ccc}x+3y-12+3x=2&|+12\\4x+2y+60-15x=1&|-60\end{array}\right\\\\\left\{\begin{array}{ccc}4x+3y=14&|\cdot2\\-11x+2y=-59&|\cdot(-3)\end{array}\right

\underline{+\left\{\begin{array}{ccc}8x+6y=28\\33x-6y=177\end{array}\right}\ \ \ \ |\text{add both sides of the equations}\\.\ \ \ \ \ \ \ 41x=205\ \ \ \ |:41\\.\ \ \ \ \ \ \ x=5\\\\\text{substitute the value of x to the first equation}\\\\4(5)+3y=14\\20+3y=14\ \ \ \ |-20\\3y=-6\ \ \ \ \ |:3\\y=-2\\\\\text{substitute the value of x to the equation:}\ z=12-3x\\\\z=12-3(5)=12-15=-3\\\\x=5,\ y=-2,\ z=-3\to(5,\ -2,\ -3)

6 0
3 years ago
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