Complete question :
The temperature at 5:00 a.m. was –6 °F. By 3:00 p.m., the temperature had risen to a high of 36 °F. If the temperature at 8:00 p.m. decreased from the high by the change in temperature in Fahrenheit degrees from 5:00 a.m. to 3:00 p.m., what was the temperature at 8:00 p.m.?
Answer:
-6°F
Step-by-step explanation:
Temperature at 5am (t1) = - 6°F
Temperature at 3pm (t2) = 36°F
Change in temperature, between 5am and 3pm:
(t2 - t1) = (36 - (-6)) = (36 + 6) = 42°F
Hence, temperature at 8:00 pm:
High temperature - change in temperature between (5am - 3pm)
36°F - 42°F = - 6°F
Respuesta Es -3 (tried my best I’m only in Spanish two my main language is English)
35.
6x=4x+16 (they are vertical angles
2x=16
x=8
4(8)+16+11y=180 (they form a straight angle together)
32+16+11y=180
48+11y=180
11y=132
y=12
36.
7x=56 (vertical angles are equivalent)
x=8
56+y+2(8)=180 (these three angles form a straight angle)
56+y+16=180
72+y=180
y=108
Hope this helps!
Answer:I don’t speak Spanish .
Step-by-step explanation:
