Could someone please help me with this problem? I don't understand.
1 answer:
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Answer:
When solving for x, answer =
When solving for a, answer =
Step-by-step explanation:
24 + 5x = -x + 6(5a - 4)
Start by multiplying 6 by the values in the parenthesis
24 + 5x = -x + 30a - 24
Add 24 to both sides of the equation
48 + 5x = -x + 30a
Add 1x to both sides of the equation
48 + 6x = 30a
Subtract 48 from both sides of the equation
6x = 30a - 48
Divide both sides of the equation by 6
x = 5a - 8 (Answer when solving for x)
Add 8 to both sides of the equation
x + 8 = 5a
Divide both sides of the equation by 5
a = 1/5x + 8/5 (Answer when solving for a)
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When solving for x, answer =
When solving for a, answer =
Hope this helps :)
Answer:
1). a = 9.42 m
2). b = 6.37 m
3). c = 4.48 m
Step-by-step explanation:
In the figure attached,
By applying tangent rule in triangle ADE,
tan47 =
c =
c =
c = 4.476
c ≈ 4.48 m
Now we apply the same rule in triangle ACE,
tan37° =
b =
b =
b = 6.37 m
Now apply the tangent in triangle ABE,
tan27° =
a =
a =
a = 9.42 m
Sense we are wanting to find <u>how many were miss</u>, then, we are practically going to subtract the following:
![\boxed{76-100}= \ \left[\begin{array}{ccc}\bf{24\end{array}\right]](https://tex.z-dn.net/?f=%5Cboxed%7B76-100%7D%3D%20%5C%20%20%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cbf%7B24%5Cend%7Barray%7D%5Cright%5D%20)
So, from this begin understood, we would then combine both the penalties that were shotted, to the onces that weren't.
So, b subtracting these both, we would grab the result, and then smash that with the number of the penalties that were made in.
Your answer:
So, from this begin understood, we would then combine both the penalties that were shotted, to the onces that weren't.
So, b subtracting these both, we would grab the result, and then smash that with the number of the penalties that were made in.
Your answer: