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Anestetic [448]
3 years ago
7

Can you help me? Please

Mathematics
1 answer:
Anni [7]3 years ago
4 0

9514 1404 393

Answer:

  a.

Step-by-step explanation:

For an even-index radical, ...

  \sqrt[n]{x^n}=|x|\qquad\text{n even}

This lets us simplify the given expression as follows:

  \sqrt[4]{81x^6y^4}-|y|\sqrt[4]{x^6}-\sqrt[4]{16x^2}=\sqrt[4]{(3xy)^4x^2}-|y|\sqrt[4]{x^4x^2}-\sqrt[4]{2^4x^2}\\\\=3|xy|\sqrt[4]{x^2}-|xy|\sqrt[4]{x^2}-2\sqrt[4]{x^2}=\boxed{2|xy|\sqrt[4]{x^2}-2\sqrt[4]{x^2}}

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Find the ratio y:x, if 3x=11y,
Aleks [24]

Answer:

3:11

Step-by-step explanation:

3x=11y

<u>Rearrange to the format of the ratio.</u>

11y = 3x

<u>Let's find </u><u>y/x</u><u>. </u><u>y/x</u><u> is </u><u>y:x.</u>

11y = 3x

<u>Divide both sides by </u><u>11</u><u>.</u>

11y/11 = 3x/11

y = 3x/11

<u>NOW LET'S DIVIDE BOTH SIDES BY </u><u>x</u><u> TO GET </u><u>x</u><u> AS THE DENOMINATOR OF </u><u>y</u><u>.</u>

y = 3x/11

y/x = (3x/11)/x

y/x = (3x/11) * 1/x

y/x = 3/11

Therefore, y:x = 3:11

Please thank, rate 5 stars, and give brainliest. Thank you.

7 0
4 years ago
Please help me with this math question I really need help ;/. I'll give brainliest if u help.
Darya [45]

Step-by-step explanation: You have to substitute the numbers in for x & y

(0, -5): YES

3x - 4y - 8 = 12

3(0) - 4(-5) - 8 = 12

0 + 20 - 8 = 12

20 - 8 = 12

12 = 12


(4, -2): YES

3x - 4y - 8 = 12

3(4) - 4(-2) - 8 = 12

12 + 8 - 8 = 12

20 - 8 = 12

12 = 12


(8, 2): NO

3x - 4y - 8 = 12

3(8) - 4(2) = 12

24 - 8 = 12

16 = 12


(-16, -17): YES

3x - 4y - 8 = 12

3(-16) - 4(-17) - 8 = 12

-48 + 68 - 8 = 12

20 - 8 = 12

12 = 12


(-1, -8): NO

3x - 4y - 8 = 12

3(-1) - 4(-8) = 12

-3 + 32 = 12

29 = 12


(-40, -34): NO

3x - 4y - 8 = 12

3(-40) - 4(-34) - 8 = 12

-120 + 136 - 8 = 12

16 - 8 = 12

8 = 12


Hope this help you!!! :)

7 0
3 years ago
Round 222,977 to the nearest hundred
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Brilliant_brown [7]
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