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Agata [3.3K]
3 years ago
15

-6+ (-20) + (-40) + 3d

Mathematics
2 answers:
makkiz [27]3 years ago
6 0

Answer: -66 + 3d   <em>or   </em>3d - 66

Step-by-step explanation:

-6 + (-20) + (-40) + 3d

-6 - 20 - 40 + 3d

-26 - 40 + 3d

-66 + 3d   or   3d - 66

Hope I helped!

satela [25.4K]3 years ago
6 0
3D-66 hope that helped
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Will give crown to best answer 20 points!!!! pls answer!!
Andrej [43]
Hello!

Significant digits are defined as all digits that determine the value of a number, excluding any zeros that act as placeholders. Let's find the number of significant digits in each option individually:

A. 0.0009462 = 4 significant digits (the zeros are placeholders)
B. 1.000150 = 7 significant digits
C. 2.0145 = 5 significant digits
D. 3.01255 = 6 significant digits

Looking at the list above, we can see that Option B has the greatest number (7) of significant digits.

The answer is Option B.

I hope this helps!
3 0
3 years ago
Find the point P on the line y=2x that is closest to the point (20,0) .what is the least distance between pans (20,0)?
Vsevolod [243]
The closest point on a line, to another point, will be a point that's on a normal of that line, or a line that is perpendicular to it, notice picture below

so, y = 2x, has a slope of 2, a perpendicular line to it, will have a slope of negative reciprocal that, or \bf 2\qquad negative\implies -2\qquad reciprocal\implies \cfrac{1}{-2}\implies -\cfrac{1}{2}

so, we know that line passes through the point 20,0, and has a slope of -1/2

if we plug that in the point-slope form, we get \bf y-0=-\cfrac{1}{2}(x-20)\implies y=-\cfrac{1}{2}x+10

now, the point that's on 2x and is also on that perpendicular line, is the closest to 20,0 from 2x, thus, is where both graphs intersect, as you can see in the graph

thus  \bf 2x=-\cfrac{1}{2}x+10  solve for "x'

------------------------------------------------------------

not sure on the 2nd part, but sounds like, what's the distance from that point to 20,0, well, if that's the case, just use the distance equation

\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ \square }}\quad ,&{{ \square }})\quad &#10;%  (c,d)&#10;&({{ \square }}\quad ,&{{ \square }})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}


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3 years ago
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Answer:

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6 0
3 years ago
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Solution:

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Here, Principal Amount = $6000

Rate of Interest =  6%

Time = 4 years

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3 years ago
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ZanzabumX [31]

Answer:

Step-by-step explanation:

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