To illustrate the information in the correct syntax:
X~N(23334, 3412²)
What we're being asked to find is P(X ≤ 26000).
In order to do this, we need to convert this value into one we can look up on the table for the standard normal distribution (Z).
To do this we use the formula:
Z = (X - μ)/σ
Z = (26000 - 23334)/3412 = 0.7813599... ⇒ 0.78
We can say:
P(X ≤ 26000) = P(Z ≤ 0.78) = 0.7823
Answer:
8 i think
Step-by-step explanation:
Answer:
Step-by-step explanation:
We are given the two functions:
And we want to find:
This is equivalent to:
So, evaluating f(-1) first, we acquire:
Then by substitution:
So:
Therefore:
Your answer is indeed correct.
Well, we know the last three numbers are:
3 (ones)
6 (tens)
7 (hundreds)
The next set is:
9 (thousands)
3 (ten thousands)
0 (hundred thousands)
And finally:
6 (millions)
5 (ten millions)
6 (hundred millions)
So we know that 5 is in ten millions.
Divide 60 and 40 by muliples to get a perfect anwser
