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notsponge [240]
2 years ago
13

What is the surface area of this design? pls help me

Mathematics
2 answers:
V125BC [204]2 years ago
6 0

Answer:

is 58in. an answer?

Step-by-step explanation:

all sides added up, 5+5=10+8=18 now the bottom, since the two sides are both 10 inches we can safely assume the other two will be 10 inches aswell, so 10+10+10+10=40.

zhuklara [117]2 years ago
5 0
The answer is 465
The top of the 5x5 is 25 plus
The sides 40x4 is 160
The bottom part is 100x2 (top and bottom are 100) 200
And the sides are 20x4 so 80 added all is 465
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Need help with this problem, it's got me stuck PLZ
faust18 [17]

24x^2 +25x - 47                     53

----------------------- = -8x -3 - ---------------

ax-2                                     ax-2

add 53/ax-2 to each side

24x^2 +25x - 47+53                    

-----------------------         = -8x -3

ax-2                                    

24x^2 +25x +6                  

-----------------------         = -8x -3

ax-2      

multiply each side by ax-2

24x^2 +25x +6   = (ax-2) (-8x-3)

multiply out the right hand side

24x^2 +25x +6  = -8ax^2 +16x-3ax +6

24 = -8a      25 = 16 -3a

a = -3          9 = -3a

                   a = -3


Choice B

6 0
3 years ago
Find the area of the region that lies inside the first curve and outside the second curve.
marishachu [46]

Answer:

Step-by-step explanation:

From the given information:

r = 10 cos( θ)

r = 5

We are to find the  the area of the region that lies inside the first curve and outside the second curve.

The first thing we need to do is to determine the intersection of the points in these two curves.

To do that :

let equate the two parameters together

So;

10 cos( θ) = 5

cos( θ) = \dfrac{1}{2}

\theta = -\dfrac{\pi}{3}, \ \  \dfrac{\pi}{3}

Now, the area of the  region that lies inside the first curve and outside the second curve can be determined by finding the integral . i.e

A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} (10 \ cos \  \theta)^2 d \theta - \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \  5^2 d \theta

A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} 100 \ cos^2 \  \theta  d \theta - \dfrac{25}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \   d \theta

A = 50 \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix}  \dfrac{cos \ 2 \theta +1}{2}  \end {pmatrix} \ \ d \theta - \dfrac{25}{2}  \begin {bmatrix} \theta   \end {bmatrix}^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}}

A =\dfrac{ 50}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix}  {cos \ 2 \theta +1}  \end {pmatrix} \ \    d \theta - \dfrac{25}{2}  \begin {bmatrix}  \dfrac{\pi}{3} - (- \dfrac{\pi}{3} )\end {bmatrix}

A =25  \begin {bmatrix}  \dfrac{sin2 \theta }{2} + \theta \end {bmatrix}^{\dfrac{\pi}{3}}_{\dfrac{\pi}{3}}    \ \ - \dfrac{25}{2}  \begin {bmatrix}  \dfrac{2 \pi}{3} \end {bmatrix}

A =25  \begin {bmatrix}  \dfrac{sin (\dfrac{2 \pi}{3} )}{2}+\dfrac{\pi}{3} - \dfrac{ sin (\dfrac{-2\pi}{3}) }{2}-(-\dfrac{\pi}{3})  \end {bmatrix} - \dfrac{25 \pi}{3}

A = 25 \begin{bmatrix}   \dfrac{\dfrac{\sqrt{3}}{2} }{2} +\dfrac{\pi}{3} + \dfrac{\dfrac{\sqrt{3}}{2} }{2} +   \dfrac{\pi}{3}  \end {bmatrix}- \dfrac{ 25 \pi}{3}

A = 25 \begin{bmatrix}   \dfrac{\sqrt{3}}{2 } +\dfrac{2 \pi}{3}   \end {bmatrix}- \dfrac{ 25 \pi}{3}

A =    \dfrac{25 \sqrt{3}}{2 } +\dfrac{25 \pi}{3}

The diagrammatic expression showing the area of the region that lies inside the first curve and outside the second curve can be seen in the attached file below.

Download docx
7 0
3 years ago
The door to the clubhouse has an area of 1,792 sq cms If the length of the door is 56cms how wide is the door ?
LuckyWell [14K]

Step-by-step explanation:

area = length x width

area = 1,792 sq cm

length = 56 sq cm

width = ?

equation = 1,792-56= 1,736

Answer:

1,736 sq cm

4 0
3 years ago
Simplify the Expression. Clear explanation of monomials appreciated - Thanks!
Nataly [62]
I think the answer is .4m^7n^8

Uhh I don’t know how to give it a clear explanation but all I did was multiply them

-0.8•-0.5= .4

M^2•m^5=m^7

n•n^7=n^8

Hope this helps some.
7 0
3 years ago
Solve 4(3x-1)=20 you may use the flowchart to help you if you wish
Korolek [52]

Answer:

x=2 : )

Step-by-step explanation:

4(3x-1)=20

12x-4=20

12x=24

x=2

5 0
3 years ago
Read 2 more answers
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