24x^2 +25x - 47 53
----------------------- = -8x -3 - ---------------
ax-2 ax-2
add 53/ax-2 to each side
24x^2 +25x - 47+53
----------------------- = -8x -3
ax-2
24x^2 +25x +6
----------------------- = -8x -3
ax-2
multiply each side by ax-2
24x^2 +25x +6 = (ax-2) (-8x-3)
multiply out the right hand side
24x^2 +25x +6 = -8ax^2 +16x-3ax +6
24 = -8a 25 = 16 -3a
a = -3 9 = -3a
a = -3
Choice B
Answer:
Step-by-step explanation:
From the given information:
r = 10 cos( θ)
r = 5
We are to find the the area of the region that lies inside the first curve and outside the second curve.
The first thing we need to do is to determine the intersection of the points in these two curves.
To do that :
let equate the two parameters together
So;
10 cos( θ) = 5
cos( θ) = 

Now, the area of the region that lies inside the first curve and outside the second curve can be determined by finding the integral . i.e









The diagrammatic expression showing the area of the region that lies inside the first curve and outside the second curve can be seen in the attached file below.
Step-by-step explanation:
area = length x width
area = 1,792 sq cm
length = 56 sq cm
width = ?
equation = 1,792-56= 1,736
Answer:
1,736 sq cm
I think the answer is .4m^7n^8
Uhh I don’t know how to give it a clear explanation but all I did was multiply them
-0.8•-0.5= .4
M^2•m^5=m^7
n•n^7=n^8
Hope this helps some.
Answer:
x=2 : )
Step-by-step explanation:
4(3x-1)=20
12x-4=20
12x=24
x=2