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tensa zangetsu [6.8K]
3 years ago
10

Which does NOT have the same Value of the expression |-8|? 19 points!

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
7 0

Answer:

I think it’s -8

Step-by-step explanation:

Genrish500 [490]3 years ago
5 0

Answer:

What are the options

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3x-5=2(2x+5) how do you slove it
DaniilM [7]

Answer:

x = -15

Step-by-step explanation:

3x-5=2(2x+5)

Expand by using distributive property

3x - 5 = 4x + 10

Subtract 4x from both sides

3x - 5 - 4x = 4x + 10 - 4x

Simplifying

-x - 5 = 10

Add 5 to both sides

-x - 5 + 5 = 10 + 5

Simplifying

-x = 15

Divide both sides by -1

x = -15

5 0
3 years ago
If x and x+30 are the pair of co - interior angle​
UkoKoshka [18]

answer in screenshot

4 0
3 years ago
Help me with this please
svp [43]
3/2
I picked a point and counted up 3 and over 2 to the next point
8 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Kitty [74]

Answer:   (-2, 5) and (2, -3)

<u>Step-by-step explanation:</u>

Graph the line y = -2x + 1 (which is in y = mx + b format) by plotting the y-intercept (b = 1) on the y-axis and then using the slope (m = -2) to plot the second point by going down 2 and right 1 unit from the first point:

        y - intercept = (0, 1)            2nd point = ( -1, 1).

Graph the parabola y = x² - 2x - 3 by first plotting the vertex and then plotting the y-intercept (or some other point):

y = x^2-2x-3\quad \rightarrow \quad a=1,\ b=-2,\ c=-3\\\\\text{axis of symmetry:}\ x = \dfrac{-b}{2a}\ \longrightarrow \ x=\dfrac{-(-2)}{2(1)}=\dfrac{2}{2}=1\\\\\text{y-value of vertex:}\ f(1) = (1)^2-2(1)-3\quad \longrightarrow \quad y = 1 - 2 - 3=-4\\\\\text{y-intercept:}\ f(0)= (0)^2-2(0)-3\ \longrightarrow \ y=0 - 0 - 3 = -3 \\

         vertex = (1, -4)                2nd point (y-intercept) = (0, -3)


<em>see attached</em> - the graphs intersect at two points:  (-2, 5) and (2, -3)


8 0
3 years ago
Please help me with this.
JulijaS [17]

The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]

<h3>How to determine the range of speed associate to desired gas mileages</h3>

In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:

g = 10 + 0.7 · v - 0.01 · v²      (1)

An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].

To learn more on quadratic functions: brainly.com/question/5975436

#SPJ1

3 0
2 years ago
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