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Slav-nsk [51]
3 years ago
5

At the beach, denise and her sister both built sandcastles and then measured their heights. Denise's sandcastle was 1 7/12 feet

tall and her sister's was 5/12 of a foot tall. How much taller was denise's sandcastle than her sister's? In mixed number
Mathematics
1 answer:
Eduardwww [97]3 years ago
7 0

Answer: 1 \frac{2}{12}\ ft

Step-by-step explanation:

The height of Denise castle is  1 \frac{7}{12}=\frac{12\times 1+7}{12}=\frac{19}{12}\ ft

height of her sister  \frac{5}{12}\ ft

Difference between the height of the castle

\Rightarrow \frac{19}{12}-\frac{5}{12}=\frac{14}{12}

In mixed fraction it is \frac{14}{12}\ or\ 1 \frac{2}{12}\ ft

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