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Stels [109]
3 years ago
15

if you flip a coin and roll a 6 sided die, what is the probability that you will flip a tails and roll 2

Mathematics
2 answers:
Stolb23 [73]3 years ago
3 0

Answer:

1/12.

Step-by-step explanation:

6 sides and 2 sides. 2 possible outcomes for each side of the dice

lesya [120]3 years ago
3 0

Answer:

\frac{1}{12}

Step-by-step explanation:

The combinations:

heads and 1, heads and 2, heads and 3, heads and 4, heads and 5, heads and 6, tails and 1, tails and 2, tails and 3, tails and 4, tails and 5, tails and 6

  1. There are 12 combinations (count if you don't believe me). An easy way to find this is by multiplying the number of things you can get from the coin (2)and the number of things you can get from the die (6).
  2. There is only one combination where you can get tails and roll 2, so the probability will be \frac{1}{12}

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Answer:

Therefore the circumference of the circle is =\frac{20\pi}{4+\pi}

Step-by-step explanation:

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and the radius of the circle be r

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The circumference of the circle is =2πr

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According to the problem,

4s + 2πr =20

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Putting the value of s

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\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}

\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25

For maximum or minimum \frac{dA}{dr}=0

Differentiating with respect to r

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\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}    > 0

For maximum or minimum

\frac{dA}{dr}=0

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\Rightarrow r=\frac{10}{4+\pi}

\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0

Therefore at r=\frac{10}{4+\pi}  , A is minimum.

Therefore the circumference of the circle is

=2 \pi \frac{10}{4+\pi}

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