I found the same problem but with given choices:
A.1 year
<span>B.2 years </span>
<span>C.3 years </span>
<span>D.4 years </span>
<span>E.6 years
</span>
profit = total revenue - total cost
p(x) = x³ - 4x² + 3x - 12
simply plug each choices to solve. answer must be 0.
A) p(1) = 1³ - 4(1²) + 3(1) - 12 = 1 - 4 + 3 - 12 = -12
B) p(2) = 2³ - 4(2²) + 3(2) - 12 = 8 - 16 + 3 - 12 = -17
C) p(3) = 3³ - 4(3²) + 3(3) - 12 = 27 - 36 + 9 - 12 = -12
D) p(4) = 4³ - 4(4²) + 3(4) - 12 = 64 - 64 + 12 - 12 = 0
E) p(6) = 6³ - 4(6²) + 3(6) - 12 = 216 - 144 + 18 - 12 = 78
It would take 4 years for the company to reach break-even point.
I'm confused to do you have an example
Answer:
x = 6
Step-by-step explanation:
<em>If </em><em>two secants</em><em> are drawn from</em><em> a point outside </em><em>the circle, then the </em><em>product</em><em> of the lengths of</em><em> one secant </em><em>and its</em><em> external segment</em><em> equals the </em><em>product </em><em>of the lengths of</em><em> the other secant </em><em>and its</em><em> external segment</em><em> </em>
Let us solve the question.
∵ There is a circle in the given figure
∵ There are two secants intersected at a point outside the circle
∵ The length of one of them = 8
∵ The length of its external segment = x
∵ The length of the other secant = 4 + 8 = 12
∵ The length of its external segment = 4
→ By using the rule above
∴ 8 × x = 12 × 4
∴ 8x = 48
→ Divide both sides by 8
∴ x = 6
<span>Pneumonoultramicroscopicsilicovolcanoconiosis has 45 letters.</span>
Answer:
<u>So, the way a ratio works is </u><u>"for every 1 of this, we have 4 of this"</u><u> for example. (the ratio I just described would be 1:4.) </u>
<u />
I believe I've seen this question before. If the ratio of dolls to teddy bears is 9:3 then for every 9 dolls you have 3 teddy bears.
So, since we have 240 dolls and a 9:3 ratio to teddy bears, all we have to do is take how many dolls we have (240) and divide it by 3 to see how many teddy bears we have.
So:
240 ÷ 3 = 80
If your ratio is 9:3, then 80 is your answer.
<u>Hope this helps and have a nice day!</u>
<u></u>
