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EastWind [94]
3 years ago
9

Drag the tiles to the correct boxes to complete the pairs. Match each expression to the correct verbal description. 8 added to t

he cube of 7x the cube of the sum of 7x and 8 7 times the cube of the sum of x and 8 8 added to the product of 7 and x cubed

Mathematics
1 answer:
QveST [7]3 years ago
6 0

Answer:

<u>A. (7x)³ + 8 ⇔ 8 added to the product of 7 and x cubed</u>

<u>B. 7x³ + 8 ⇔ 8 added to cube of 7x</u>

<u>C. 7 (x + 8)³ ⇔ 7 times the cube of the sum of x and 8</u>

<u>D.  (7x + 8)³ ⇔ the cube of the sum of 7x and 8</u>

Step-by-step explanation:

1. Let's drag the tiles to the correct boxes to complete the pairs.

A. (7x)³ + 8 ⇔ 8 added to the product of 7 and x cubed

The second tile was already given and solved, however we're copying it.

B. 7x³ + 8 ⇔ 8 added to cube of 7x

C. 7 (x + 8)³ ⇔ 7 times the cube of the sum of x and 8

We use the expression 7 times because number 7 is multiplying the sum inside the parenthesis.

D.  (7x + 8)³ ⇔ the cube of the sum of 7x and 8

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dmitriy555 [2]
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3 0
3 years ago
Show that: (3x-1)(x+5)(4x-3) = 12x^3 + 47x^2 - 62x +15 for all values of x. (3x-1)(x+5)(4x-3) = (?????)(4x-3) Expand into 6 term
lara31 [8.8K]
<span>(3x - 1)( x + 5)(4x - 3) = 12x^3 + 47x^2 - 62x +15 </span>
<span>(3x^2 – x + 15x - 5)( 4x – 3 ) = <span>12x^3 + 47x^2 - 62x +15 </span></span>
<span>(3x^2 + 14x - 5)( 4x – 3 ) = <span>12x^3 + 47x^2 - 62x +15 </span></span>
<span>12x^3 – 9x^2 + 56x^2 – 42x – 20x + 15 = <span>12x^3 + 47x^2 - 62x +15 </span></span>
<span>12x^3 – 47x^2 - 62x + 15 = <span>12x^3 + 47x^2 - 62x +15 </span></span>

<span> </span>

8 0
3 years ago
Read 2 more answers
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