All categories

3 years ago

Can anyone tell me the rules for rounding of digits? plz ASAP

Mathematics

2 answers:

Iteru [2.4K]3 years ago

4 0

Answer:

u use the closest number to the number u are rounding up to round it up.if it is 0-4 u round it to 0and add to the number while if it is 5-9 u round it up to 1 and add to the number.after all rounding up the number used to round up downwards will be converted to 0s

natita [175]3 years ago

4 0

Answer:

If the ones place has a number less than 4, the tens stay the same with a zero in the ones place. If the ones place has a number more than 5, the tens will have another ten. If the ones place has a number 5 in the ones place, then you round the tens to the next ten.

Examples: 37=40 73=70 65=70

You might be interested in

What is the equation of the following line written in slope intercept form? (-5,-1)

solmaris [256]

Answer:

$\large\boxed{y=-\dfrac{2}{3}x-\dfrac{13}{3}}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

From the graph we have two points (-5, -1) and (-2, -3).

Look at the picture.

Calculate the slope:

$m=\dfrac{-3-(-1)}{-2-(-5)}=\dfrac{-2}{3}=-\dfrac{2}{3}$

Put it to the equation in slope-intercept form:

$y=-\dfrac{2}{3}x+b$

We can't read the y-intercept from the graph. Therefore put the coordinates of the point (-5, -1) to the equation and calculate b:

$-1=-\dfrac{2}{3}(-5)+b$

$-1=\dfrac{10}{3}+b$ subtract 10/3 from both sides

$-\dfrac{3}{3}-\dfrac{10}{3}=b\to b=-\dfrac{13}{3}$

Finally:

$y=-\dfrac{2}{3}x-\dfrac{13}{3}$

4 0

3 years ago

Find the equation of the inverse.<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%7B2%7D%5E%7Bx%20%2B%205%7D%20%20-%206" id="TexF

Contact [7]

Find the equation of the inverse.

$y = {2}^{x + 5} - 6$

we have

$y=\mleft\{2\mright\}^{\mleft\{x+5\mright\}}-6$

step 1

Exchange the variables

x for y and y for x

$x=\{2\}^{\{y+5\}}-6$

step 2

Isolate the variable y

$(x+6)=2^{(y+5)}$

apply log both sides

$\begin{gathered} \log (x+6)=(y+5)\cdot\log (2) \\ y+5=\frac{\log (x+6)}{\log (2)} \\ \\ y=\frac{\log(x+6)}{\log(2)}-5 \end{gathered}$

step 3

Let

$f^{(-1)}(x)=y$

therefore

the inverse function is

$f^{(-1)}(x)=\frac{\log(x+6)}{\log(2)}-5$

7 0

1 year ago

Mandy has a 10.2-ounce container of mustard. She uses 130 of the mustard to put on her hot dog each time. How many ounces of mus

Marianna [84]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

If a polynomial cannot be written as the product of two other polynomials (excluding 1 and minus−1), then the polynomial is sa

Anni [7]

In mathematics, a polynomial is an algebraic expression containing more than two terms. When the polynomial could not be reduced to a lower degree, it is classified as a prime polynomial. Just like whole numbers, a prime polynomial cannot be broken down into factors except 1 and by the number itself. Take for example, the polynomial x² + 5x + 6. It can be reduces to its factors x=-2 and -3. That would be expressed to x² + 5x + 6 = (x+2)(x+3). But if the polynomial is, say, x² + 5x + 7, there is no roots that are whole numbers. Therefore, it can't be reduced into factored groups because it is a prime polynomial.

5 0

3 years ago

Write the standard form of the line that passes through (-1,-3) and (2,1).

kobusy [5.1K]

Answer:

Step-by-step explanation:

$\mathrm{Line\:passing\:through\:}\left(-1,\:-3\right)\mathrm{,\:}\left(2,\:1\right)\\\\\mathrm{Find\:the\:line\:}\\\mathbf{y=mx+b}\mathrm{\:passing\:through\:}\left(-1,\:-3\right)\mathrm{,\:}\left(2,\:1\right)\\\\\mathrm{Compute\:the\:slope\:}\left(-1,\:-3\right),\:\left(2,\:1\right):\quad \\m=\frac{4}{3}\\\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(-1,\:-3\right),\:\left(x_2,\:y_2\right)\\\left\\$

$\\m=\frac{1-\left(-3\right)}{2-\left(-1\right)}\\\\Refine\\\\m=\frac{4}{3}\\\\\mathrm{Compute\:the\:}y\mathrm{\:intercept}:\quad b=-\frac{5}{3}\\\\y=\frac{4}{3}x-\frac{5}{3}\\$

Convert equation to standard form

$y - \frac{4}{3} x + \frac{5}{3} = 0\\\\Multiply \:through\: by\: 3;\\\\3\times (y - \frac{4}{3} x + \frac{5}{3} )=0\\\\3y -4x+5 = 0\\Arrange\:n\:form\:of \:;\\Ax +By = C\\\\-4x +3y =-5$

5 0

3 years ago