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3 years ago

If anybody can help me with questions 1-4 that will be awesome. YOUR A LIFE SAVER!!!

Mathematics

2 answers:

GrogVix [38]3 years ago

6 0

Answer:

1. D

2. C

3. D

4. B

Step-by-step explanation:

Gelneren [198K]3 years ago

6 0

Answer:

1) D

2) C

3) D

4) B

Step-by-step explanation:

Background info: Left pointing vector is less than, right pointing is greater than. A circle without the middle filled in shows that value is excluded, a full circle shows included(which would be greater than or equal to, and less than or equal to)

With that you look at the sign for each problem and apply what I wrote above.

For example for question 1, x is greater than or equal to 8 so you pick the right/positive arrow, and the filled in circle.

Hope this helps!

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What is 10√94 simplified. Its not 98 or its decimal form.

slavikrds [6]

Answer:

Step-by-step explanation:

i think 96(probably)

have a nice day

3 0

3 years ago

SOMEONE PELASE HELP ME ASAP! I REALLY NEED HELP ASAP

Stells [14]

Answer: below in picture

explanation: also in picture

6 0

3 years ago

Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen

SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = $\frac{4!}{1! (4 - 1 )!}$ × $\frac{6!}{2! (6 - 2 )!}$

= $\frac{4!}{(3)!}$ × $\frac{6!}{2! (4)!}$

= $\frac{4.3!}{(3)!}$ × $\frac{6.5.4!}{2! (4)!}$

= $4$ × $\frac{6.5}{2.1! }$

= $4$ × $15$ = 60

Total Number of possibility = ¹⁰C₃ = $\frac{10!}{3! (10-3)!}$

= $\frac{10!}{3! (7)!}$

= $\frac{10.9.8.7!}{3! (7)!}$

= $\frac{10.9.8}{3.2.1!}$

= 120

So, probability = $\frac{60}{120} = \frac{1}{2} = 0.5$

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility = ⁴C₀ × ⁶C₃

= $\frac{4!}{0! (4 - 0)!}$ × $\frac{6!}{3! (6 - 3)!}$

= $\frac{4!}{(4)!}$ × $\frac{6!}{3! (3)!}$

= 1 × $\frac{6.5.4.3!}{3.2.1! (3)!}$

= 1× $\frac{6.5.4}{3.2.1! }$

= 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = $\frac{80}{120} = \frac{8}{12} = 0.66$

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility = ⁴C₂ × ⁶C₁

= $\frac{4!}{2! (4 - 2)!}$ × $\frac{6!}{1! (6 - 1)!}$

= $\frac{4!}{2! (2)!}$ × $\frac{6!}{1! (5)!}$

= $\frac{4.3.2!}{2! (2)!}$ × $\frac{6.5!}{1! (5)!}$

= $\frac{4.3}{2.1!}$ × $\frac{6}{1}$

= 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility = ⁴C₃ × ⁶C₀

= $\frac{4!}{3! (4 - 3)!}$ × $\frac{6!}{0! (6 - 0)!}$

= $\frac{4!}{3! (1)!}$ × $\frac{6!}{(6)!}$

= $\frac{4.3!}{3!}$ × 1

= 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = $\frac{100}{120} = \frac{10}{12} = 0.83$

3 0

3 years ago

An item is priced at $13.13. If the sales tax is 5%, what does the item cost including sales tax?

V125BC [204]

Answer:

$13.79

Step-by-step explanation:

13.13x0.05=0.6565

Tax=0.66

13.13+0.66=13.79

8 0

3 years ago

A moose population is growing exponentially following the pattern in the table shown below. Assuming that the pattern continues,

Alika [10]

The population of the moose after 12 years is 7692

Step-by-step explanation:

The form of the exponential growth function is $y=a(b)^{x}$ , where

a is the initial value
b is the growth factor

The table:

→ x : y

→ 0 : 40

→ 1 : 62

→ 2 : 96

→ 3 : 149

→ 4 : 231

To find the value of a , b in the equation use the data in the table

∵ At x = 0 , y = 40

- Substitute them in the form of the equation above

∵ $40=a(b)^{0}$

- Remember any number to the power of zero is 1 (except 0)

∴ 40 = a(1)

∴ a = 40

- Substitute the value of a in the equation

∴ $y=40(b)^{x}$

∵ At x = 1 , y = 62

- Substitute them in the form of the equation above

∵ $62=40(b)^{1}$

∴ 62 = 40 b

- Divide both sides by 40

∴ 1.55 ≅ b

∴ The growth factor is about 1.55

- Substitute its value in the equation

∴ The equation of the population is $y=40(1.55)^{x}$

To find the population of moose after 12 years substitute x by 12 in the equation

∵ $y=40(1.55)^{12}$

∴ y ≅ 7692

The population of the moose after 12 years is 7692

Learn more:

You can learn more about the logarithmic functions in brainly.com/question/11921476

#LearnwithBrainly

7 0

3 years ago