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scoray [572]
3 years ago
11

Linear graphing y= -2x

Mathematics
1 answer:
Vlad1618 [11]3 years ago
3 0
Let x = 0. What do you get for y?
This gives you one point.

Then let x = 1. What do you get for y.
This gives you a second point.
You might be interested in
Please help and thank you
masya89 [10]

Answer:

B. 407

Step-by-step explanation:

equation: y= A(1- r/n)^nt

y=471(1-(.07/1))^1(2)

you should get 407.37 as your answer

3 0
3 years ago
Read 2 more answers
Nemecek Brothers make a single product on two separate production lines, A and B. Its labor force is equivalent to 1000 hours pe
frez [133]

Answer:

(a) The inequality for the number of items, x, produced by the labor, is given as follows;

250 ≤ x ≤ 600

(b) The inequality for the cost, C is $1,000 ≤ C ≤ $3,000

Step-by-step explanation:

The total time available for production = 1000 hours per week

The time it takes to produce an item on line A = 1 hour

The time it takes to produce an item on line B = 4 hour

Therefore, with both lines working simultaneously, the time it takes to produce 5 items = 4 hours

The number of items produced per the weekly labor = 1000/4 × 5 = 1,250 items

The minimum number of items that can be produced is when only line B is working which produces 1 item per 4 hours, with the weekly number of items = 1000/4 × 1 = 250 items

Therefore, the number of items, x, produced per week with the available labor is given as follows;

250 ≤ x ≤ 1250

Which is revised to 250 ≤ x ≤ 600 as shown in the following answer

(b) The cost of producing a single item on line A = $5

The cost of producing a single item on line B = $4

The total available amount for operating cost = $3,000

Therefore, given that we can have either one item each from lines A and B with a total possible item

When the minimum number of possible items is produced by line B, we have;

Cost = 250 × 4 = $1,000

When the maximum number of items possible, 1,250, is produced, whereby we have 250 items produced from line B and 1,000 items produced from line A, the total cost becomes;

Total cost = 250 × 4 + 1000 × 5 = 6,000

Whereby available weekly outlay = $3000, the maximum that can be produced from line A alone is therefore;

$3,000/$5 = 600 items = The maximum number of items that can be produced

The inequality for the cost, C, becomes;

$1,000 ≤ C ≤ $3,000

The time to produce the maximum 600 items on line A alone is given as follows;

1 hour/item × 600 items = 600 hours

The inequality for the number of items, x, produced by the labor, is therefore, given as follows;

250 ≤ x ≤ 600

8 0
3 years ago
Which statement is true about 143? A. It is a prime number. B. It is a composite number. C. It is a whole number that is neither
Stels [109]

Answer:

B. It is a composite number.

Step-by-step explanation:

143 can be divided by 11 and 13 making it a composite number.

5 0
3 years ago
Read 2 more answers
If x =2 find the value of q in the equation 3x-4=x+q​
Effectus [21]

Step-by-step explanation:

given x=2

and the equation

3x - 4 = x + q

to find the value of q , you need to make q the subject in the equation as shown below

q= 3x-x -4

q=2x-4

but x= 2

so just substitute the value of x in the equation for the q

q = 2(2) - 4

q=4-4

q=0

therefore the value of q is 0

5 0
3 years ago
XYZ Corporation operates two plants, each of which has a capacity of 100 units per day. Each day, XYZ must ship their product to
Strike441 [17]

9514 1404 393

Answer:

  1. {20, 20, 20, 40} units to {A, B, C, D}
  2. {0, 0, 0, 100}

  minimum shipping cost: 3000

Step-by-step explanation:

In general, shipping costs more from Plant 1. The excess costs to ship to customers A, B, C, D are, respectively, (24-18) = 6, (21-16) = 5, (19-19) = 0, (18-10) = 8.

The greatest excess cost is for shipping to customer D from plant 1, so we want to ship as many units as possible to customer D from plant 2.

Shipments from Plant 2 to Customers {A, B, C, D} = {0, 0, 0, 100}.

Then the remaining shipments are fulfilled from Plant 1.

Shipments from Plant 1 to Customers {A, B, C, D} = {20, 20, 20, 40}.

The amount spent on shipping each day is ...

  100×10 +20×24 +20×21 +20×19 +40×18

  = 20×(50 +24 +21 +19 +36) = 3000 . . . . daily shipping cost

6 0
2 years ago
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