Uhhhh I don't think that the correct answer.
First, find the gradient of the line segment.
Gradient = Rise/Run = (2-6)/(2-5) = 4/3.
Since the other line segment is parallel to this line segment, their gradients are the same.
That means (-2+4)/(x-5) = 4/3.
2/(x-5) = 4/3
It is obvious x = 6.5
Answer:
f(x) and g(x) are inverse functions
Step-by-step explanation:
In the two functions f(x) and g(x) if, f(g(x)) = g(f(x)) = x, then
f(x) and g(x) are inverse functions
Let us use this rule to solve the question
∵ f(x) = 3x²
∵ g(x) = 
→ Find f(g(x)) by substitute x in f(x) by g(x)
∴ f(g(x)) = 3(
)²
→ Cancel the square root with power 2
∴ f(g(x)) = 3(
)
→ Cancel the 3 up with the 3 down
∴ f(g(x)) = x
→ Find g(f(x)) by substitute x in g(x) by f(x)
∴ g(f(x)) = 
→ Cancel the 3 up with the 3 down
∴ g(f(x)) = 
→ Cancel the square root with power 2
∴ g(f(x)) = x
∵ f(g(x)) = g(f(x)) = x
→ By using the rule above
∴ f(x) and g(x) are inverse functions
The simplified expression of
is 
<h3>How to simplify the expression?</h3>
The expression is given as:

Divide 162 and 2 by 2

Take the square root of 81

Apply the quotient rule of indices

Evaluate the difference

Take the square root of x^18

Hence, the simplified expression of
is 
Read more about expressions at:
brainly.com/question/723406
#SPJ1
Answer:
The expression would give the probability that one marble is yellow and the other marble is red is,

Step-by-step explanation:
A bag contains eight yellow marbles, nine green marbles, three purple marbles, and five red marbles. So in total there are 25 marbles.
Hence,
Probability of getting yellow ball = 
Probability of getting red ball = 
Probability that one marble is yellow and the other marble is red is,

The answer is C) 0
Because math