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2 years ago

Pls help it's a redo assignment

Mathematics

1 answer:

umka21 [38]2 years ago

3 0

Answer:

a) 8 1/3 b) 1 c) 4 7/8 d) 9 3/5 e) 3 1/6 f) 84 g) 8 h) 4 8/15 i) 20

Step-by-step explanation:

Just trust me

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bryan says all prime numbers are odd numbers list all the prime numbers less than 20 in a numerical order

Greeley [361]

This is a list of all the prime numbers less than 20 in numerical order

6 0

2 years ago

Let y = In x and V = lny. Write Inyx in terms of u and v.

weqwewe [10]

Answer:

v + u

Step-by-step explanation:

Using the rule of logarithms

log x + log y ⇔ log xy

Given

ln yx, then

ln yx = ln y + ln x = v + u

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3 years ago

4. Add<br> f(x)= 4x?+5x-1<br> g(x) = 2x2 + 5x+3

Maurinko [17]

<h3>Answer:</h3>

A. 3x² +6

<h3>Explanation:</h3>

(f-g)(x) = f(x) -g(x) = (4x²+1) -(x²-5) . . . . . substitute the function definitions

... = 4x² +1 -x² +5 . . . . . . . . . . . eliminate parentheses

... = (4-1)x² +(1+5) . . . . . . . . . . . collect like terms

... = 3x² +6

6 0

2 years ago

The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.

valina [46]

Answer:

A sample of 179 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.85}{2} = 0.075$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.075 = 0.925$ , so Z = 1.44.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

A previous study found that for an average family the variance is 1.69 gallon?

This means that $\sigma = \sqrt{1.69} = 1.3$

If they are using a 85% level of confidence, how large of a sample is required to estimate the mean usage of water?

A sample of n is needed, and n is found for M = 0.14. So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.14 = 1.44\frac{1.3}{\sqrt{n}}$

$0.14\sqrt{n} = 1.44*1.3$

$\sqrt{n} = \frac{1.44*1.3}{0.14}$

$(\sqrt{n})^2 = (\frac{1.44*1.3}{0.14})^2$

$n = 178.8$

Rounding up

A sample of 179 is needed.

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3 years ago

______ an argument which convinces other people that something is true

Alina [70]

Answer:

Step-by-step explanation:

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3 years ago

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