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3 years ago

2.1(0.2x-1.4)=1.3(0.4x—3.5) Pls help.

Mathematics

2 answers:

Talja [164]3 years ago

6 0

PLEASE FOLLOW ME

Answer:

hope it helps..

Step-by-step explanation:

Simplifying

2.1(0.2x + -1.4) = 1.3(0.4x + -3.5)

Reorder the terms:

2.1(-1.4 + 0.2x) = 1.3(0.4x + -3.5)

(-1.4 * 2.1 + 0.2x * 2.1) = 1.3(0.4x + -3.5)

(-2.94 + 0.42x) = 1.3(0.4x + -3.5)

Reorder the terms:

-2.94 + 0.42x = 1.3(-3.5 + 0.4x)

-2.94 + 0.42x = (-3.5 * 1.3 + 0.4x * 1.3)

-2.94 + 0.42x = (-4.55 + 0.52x)

Solving

-2.94 + 0.42x = -4.55 + 0.52x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-0.52x' to each side of the equation.

-2.94 + 0.42x + -0.52x = -4.55 + 0.52x + -0.52x

Combine like terms: 0.42x + -0.52x = -0.1x

-2.94 + -0.1x = -4.55 + 0.52x + -0.52x

Combine like terms: 0.52x + -0.52x = 0.00

-2.94 + -0.1x = -4.55 + 0.00

-2.94 + -0.1x = -4.55

Add '2.94' to each side of the equation.

-2.94 + 2.94 + -0.1x = -4.55 + 2.94

Combine like terms: -2.94 + 2.94 = 0.00

0.00 + -0.1x = -4.55 + 2.94

-0.1x = -4.55 + 2.94

Combine like terms: -4.55 + 2.94 = -1.61

-0.1x = -1.61

Divide each side by '-0.1'.

x = 16.1

Simplifying

x = 16.1

Tresset [83]3 years ago

3 0

Answer:

x=161/10 =16.100

Step-by-step explanation:

Combine Like Terms

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a. If a sample of size 200 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 41.26%.

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Step-by-step explanation:

This problem should be solved with a binomial distribution sample, but as the size of the sample is large, it can be approximated to a normal distribution.

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We can now calculate the probabilities:

$P(0.47$

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We can calculate the z values for x1=0.47 and x2=0.51:

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We can now calculate the probabilities:

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If a sample of size 100 is taken, the probability that the proportion of successes in the sample will be between 0.47 and 0.51 is 30.5%.

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