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Svetlanka [38]
2 years ago
7

Sue has 20 biscuits in a tin There are 12 plain biscuits 5 chocolate biscuits 3 currant biscuits Sue takes at 2 random biscuits

from the tin Work out the probability that the 2 biscuits were not the same time
Mathematics
1 answer:
vagabundo [1.1K]2 years ago
7 0

Answer:

111 / 190

Step-by-step explanation:

Total biscuits = 20

Plain, P = 12

Chocolate, C = 5

Currant, K = 3

Assume without replacement :

Probability that biscuit are of the same type :

P(plain) :

12 / 20 * 11 / 19 = 132 / 380

P(chocolate) :

5/ 20 * 4 / 19 = 20/ 380

P(currant) :

3/20 * 2 /19 = 6 / 380

Therefore,

Probability that biscuit is of the same type :

P(plain) + P(chocolate) + P(currant)

132/380 + 20/380 + 6/380

158 / 380 = 79 / 190

Therefore, probability that biscuit aren't of the same type :

1 - P(biscuit is of same type)

1 - 79/190

(190 - 79) / 190

111 / 190

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3 years ago
Molly tried to evaluate 93\times5193×5193, times, 51 using partial products. Her work is shown below.
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Since molly's solution tally's with the given solution, hence <em>Molly's solution is correct.</em>

Given the working on a partial product of 93 and 51 carried out by Molly as shown:

\begin{array}{llrr} &&93 \\ &&\underline{{}\times51} \\ &\blueD{\text{Step 1}}&\blueD{3}& \blueD{1\times3\text{ ones}}\\ &\greenD{\text{Step 2}}&\greenD{90}& \greenD{1\times 9\text{ tens}}\\ &\maroonD{\text{Step 3}}&\maroonD{150}& \maroonD{50\times 3\text{ ones}}\\ &\goldE{\text{Step 4}}&\underline{{}+\goldE{ 4{,}500}}& \goldE{50\times 9\text{ tens}}\\ &\purpleD{\text{Step 5}}&\purpleD{4{,}743}& \end{array}​

This partial product can also be solved as shown below:

93 \times 51 = (90+3)\times (50+1)

Applying the distributive law:

93 \times 51 = 90(50) + 90(1) + 3(50) + 3(1)\\93 \times 51 =4500 + 90 + 150 + 3\\93 \times 51 =4500+240+3\\93 \times 51 =4740+3\\93 \times 51 =4743

Since molly's solution tally's with the given solution, hence <em>Molly solution is correct.</em>

Learn more about partial product at: brainly.com/question/24716925

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