Answer:
The solution is in the attached file below
Answer: 68
Explanation:
Let x be the age of Mr Jasmi
y be the age of Miss Haslinda
a + b + c be the age of the 3 children
We can write:
(x + y + a + b + c)/5 = 38
But:
(a + b + c)/3 = 18
a + b + c = 18(3)
a + b + c = 54
Substitute this value to our first equation
(x + y + 54)/5 = 38
x + y + 54 = 38(5)
x + y + 54 = 190
x + y = 190 - 54
x + y = 136
Thus:
Mean age of (mr jasmi and miss Linda) = (x+y)/2
But x + y = 136
=> mean age = 136/2 = 68
6/9 (2/3) and 2/3. Hope this helps you.
This can be expressed as exponential growth of the form:
f=ir^t, f=final amount, i=initial amount, r=common ratio (rate), t=time
In this case we are given the point (2, 6500) and i=5000 so we can solve for the rate...
6500=5000r^2 divide both sides by 5000
1.3=r^2 take the square root of both sides and note that we know r>0
r=1.3^(1/2) so our equation becomes:
f=5000(1.3)^(1/2)^t and knowing that (a^b)^c=a^(b*c) we can say:
f=5000(1.3)^(t/2) so for t=18
f=5000(1.3)^9
f≈53022 (to nearest whole bacteria)
