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solniwko [45]
3 years ago
6

Help! 9% ___ 0.4 it's an inequality

Mathematics
1 answer:
devlian [24]3 years ago
4 0
9% is less than 0.4. 0.4 is really 4/10 which is 40% 40 is greater than 9 therefore 9% is less than 0.4
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Equivalent radical expression of X^1/2
saveliy_v [14]

go on the apps to download it will help you alot with this equation

3 0
3 years ago
PLEASE HELP ME WITH THIS MATH PROBLEM
Viefleur [7K]

Answer:

22π

Step-by-step explanation:

The area formula for a sector is

A=\frac{\theta }{360}*\pi  r^2

The angle theta is to be the angle that is a part of the sector for which we are trying to find the area.  If we are looking for the area of the larger sector, we are not using 140 as our angle theta, we are using 360 - 140 = 220 as our angle theta since that is the angle for the larger of the 2 sectors.  Filling in our formula using r = 6:

A=\frac{220}{360}*36\pi

The easiest way to handle this math is to multiply the 220 by the 36, hit enter on your calculator, then divide that product by 360.  When you do that your answer, in terms of pi, is 22π

5 0
3 years ago
I need help pls.............
Sever21 [200]

Answer:

  • P = 6750n +7800r
  • n ≤ 19
  • r ≤ 31
  • 160n +620r ≤ 8110
  • n = 19
  • r = 8
  • 190,650 people

Step-by-step explanation:

This linear programming problem is described by an objective function and constraints on the variables. A graphical solution works well.

<h3>Objective function</h3>

The goal is to maximize the number of people exposed to the company's ad(s). The number of people reached is the sum of the products of the number of ads and the number reached per ad.

For n newspaper ads, we are told that 6750n people are reached.

For r radio ads, we are told that 7800r people are reached.

The total number of people reached is ...

  P = 6750n +7800r . . . . . . . the function we wish to maximize

<h3>Newspaper ads</h3>

We can run at most 19 newpaper ads:

  n ≤ 19

<h3>Radio ads</h3>

We can run at most 31 radio ads:

  r ≤ 31

<h3>Budget</h3>

The cost of n newspaper ads will be $160n.

The cost of r radio ads will be $620r.

We must stay within a budget for the ads, $8100:

  160n +620r ≤ 8110

<h3>Solution</h3>

The white area in the first quadrant of the attached graph represents the feasible solution space. (We reversed the inequality symbol in each inequality so the solution space would be white, not triple-shaded.) The corners of the solution space represent possible (n, r) pairs where the objective function might be maximized.

The solid red line on the graph shows the maximum value the objective function might have, and the (n, r) pairs that would give that maximum value. The value of the objective function increases the farther the line is from the origin. Drawing the line on the graph lets us readily identify the (n, r) coordinate pair that will place this line as far as possible from the origin, maximizing P. We find that to be (n, r) = (19, 8).

  • the number of newspaper ads to run is 19
  • the number of radio ads to run is 8
  • the group exposure is (6750)(19) +(7800)(8) = 190,650

3 0
1 year ago
Andy paints 3 rooms in 7 hours. at the same pace, how long would it take to paint 15 rooms.
Dominik [7]

Answer:

105

Step-by-step explanation:

15 x 7

3 0
3 years ago
Someone help me please
oksian1 [2.3K]

Answer: 12

Step-by-step explanation:

Let's say that the length needed to be found is x
As the two lengths of both triangles are parallel to one another, we can use the equation to find x
6/x = (6+4)/20

6/x = 1/2

x = 12

4 0
2 years ago
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