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2 years ago

What is the rate of change of y with respect to x of the linear function represented by the table below?

Mathematics

1 answer:

Aleks [24]2 years ago

6 0

Answer:

$- \frac{9}{2}$

Step-by-step explanation:

12-3 for the change from the y-intercept

9/-2

$- \frac{9}{2}$

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Combine as indicated by the signs. 4/ y^2-9 + 5/y+3

natka813 [3]

$\frac{4}{y^{2}-9 } + \frac{5}{y+3} = \frac{4}{(y-3)(y+3) } + \frac{5}{y+3}= \frac{4}{(y-3)(y+3) } + \frac{5(y-3)}{(y-3)(y+3)}=
\\ \\=\frac{4}{(y-3)(y+3) } + \frac{5y-15}{(y-3)(y+3)}= \frac{5y-11}{(y-3)(y+3)}=\frac{5y-11}{y^{2}-9}
$

8 0

3 years ago

Jug A has 0.1 litres more than jug B. Jug C has 200 millilitres less than jug B. Jug D has ¼ of the amount that is in jug A. The

Gnesinka [82]

Answer:

A = 0.8 litres

B = 0.7 litres

C = 0.5 litres

D = 0.2 litres

Step-by-step explanation

Here's what we know:

1. Jug A = B + .1 litres

2. Jug C = B - 200 (or 0.2 litres)

3. Jug D = .25 x A

4. Jug A + Jug B = 1.5 litres

In problem 1, we learned that Jug A has .1 litres more than Jug B and in problem 4, the two of them added together are 1.5 litres. To solve this we can combine the problems.

B + .1 litres + B = 1.5 litres

2B + .1 = 1.5

Subtract .01 from each side and you have 2B = 1.4

Divide each side by 2 and you have B = 0.7 litres

Plug this info into problem 1 and you can solve for A. (0.7 + 0.1 = 0.8)

Plug this info into problem 2 and you can solve for C. (0.7 - 0.2 = 0.5)

Since you have A, you can use that info to solve problem 3 (0.25 x 0.8 = 0.2)

8 0

2 years ago

Which best describes the transformation that occurs from the graph of f(x) = x2 to g(x) = (x – 2)2 + 3?

Andrei [34K]

Answer:

A. right 2, up 3

Step-by-step explanation:

We have that,

The function $f(x) = x^2$ is transformed to $g(x) =(x- 2)^2+3$ .

We see that,

The function f(x) is translated 2 units to the right and 3 units upwards to obtain the function g(x).

So, the correct transformation is 'right 2, up 3'.

Hence, option A is correct.

5 0

3 years ago

Read 2 more answers

The given lengths are two sides of a right triangle. All three side lengths of the triangle are integers and together form a pyt

Leni [432]

If all three side lengths are INTEGERS and form PYTHAGOREAN TRIPLE then we know decimals are not allowed

if 24 and 51 are both legs then
$24^{2} + 51^{2} = x^{2}$
x = 3177
and squre root of that gives us 56.364.... NOT an integer

So that means one of them is not a leg and since hypotenuse is longer than both legs, 51 must be the hypotenuse so to get the third side

$51^{2} - 24^{2} = x^{2}[tex] [tex] x^{2}$ =2025
x=45, leg B

7 0

2 years ago

F(x)=1/2x+4 For R={5,6,7,8}

anzhelika [568]

Hey there!!

Remember : R = range and f ( x ) = y and y = range

R : { 5 , 6 , 7 , 8 }

( 1 ) 5 = 1 x / 2 + 4

... 5 - 4 = x / 2

... 1 = x / 2

... x = 2 = ( 2 , 5 )

( 2 ) 6 = x / 2 + 4

... 2 = x / 2

... x = 4 = ( 4 , 6 )

( 3 ) 7 = x / 2 + 4

... 3 = x / 2

... x = 6 = ( 6 , 7 )

( 4 ) 8 = x /2 + 4

... 4 = x/2

... x = 8 = ( 8 , 8 )

Hope my answer helps!

7 0

3 years ago