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zloy xaker [14]
3 years ago
14

If a ball is thrown straight up with an initial velocity of 29.4 m/s, the

Mathematics
2 answers:
zaharov [31]3 years ago
5 0

Answer:

after 6 seconds in the air

Step-by-step explanation:

setting 'h' equal to zero will yield when the ball returns to the ground

you can factor out -4.9t to get:

-4.9t(t - 6) = 0

t = 0 (prior to ball being thrown)

t = 6 (this means, after 6 seconds, the height of the ball is back to zero)

katovenus [111]3 years ago
3 0

Answer:

6 sec

Step-by-step explanation:

when ball return to the ground, h is 0

0=at^2 +bt

0 = -4.9t^2+29.4t

factor: -4.9 times -6 is 29.4

0 = -4.9t(t-6)

set each equation to 0

-4.9t = 0 or t-6=0

t = 0 or t= 6

it's 6 seconds

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Answer:

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function printMagic(s) {

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}

function checkSet(set) {

   let counter = 1;

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       if (checkIfInSet(i, set) && checkIfMagic(i.toString())) {

           console.log(`--${counter++}-- (of set ${set})`);

           printMagic(i.toString());

       }

   }

}

checkSet('23456');

checkSet('34567');

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