It would show the average time spent on the homework.
And the average distance between the mean and the lowest and highest numbers in the data.
<u>9x</u> = <u>3y + 5</u>
9 9
x = 1/3y + 5/9
x - 5/9 = 1/3y + 5/9 - 5/9
x - 5/9 = 1/3y
3(x - 5/9) = 1/3y · 3
3x - 1 2/3 = y
y = 3x - 1 2/3
When x=-1:

Ok that gives us a little more information.
If we implicitly differentiate with respect to t, from the very start, then we can apply our product rule, ya?

The right side is zero, derivative of a constant is zero.
Where x' is dx/dt and y' is dy/dt.
From here, plug in all the stuff you know:
y' = -3
x = -1
y = 4
and solve for x'.
Hope that helps!
Answer:
I think 3 ............................three

<u>Answer</u><u>:</u>
<u>a.</u><u> </u><u>7</u>
Hope you could understand.
If you have any query, feel free to ask.