Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
Answer:
The GCF for the variable part is ab².
GCF<em>Variable</em>=ab²
Multiply the GCF of the numerical part 5 and the GCF of the variable part ab².
5ab²
Step-by-step explanation:
8 is to 64 as 2 is to 16
x=16
Answer:
$6261.61
Step-by-step explanation:
The solution to the differential equation is the exponential function ...
A(t) = 5000e^(0.0225t)
We want the account value after 10 years:
A(10) = 5000e^(0.225) = 6261.61
The value of the account after 10 years will be $6,261.61.
_____
The rate of change equation basically tells you that interest is compounded continuously. After working interest problems for a while you know the formula for that is the exponential formula A = A0·e^(rt).
Or, you can solve the differential equation using separation of variables:
dA/A = 0.0225dt
ln(A) = 0.0225t +C . . . . integrate
A(t) = A0·e^(0.0225t) = 5000·e^(0.0225t) . . . . solution for A(0) = 5000
Answer:
Looking at the first question, it's asking what best describes the probability of tossing a number less than 6 on a number cube that has 6 numbers. Impossible means that it will never land on it, for example asking what the probability of landing on 7 is. Unlikely is something that doesn't happen often. The best option that fits our scenario is option C, likely.
Looking at the second question, it's asking what the probability that the teacher chooses a girl in his class. There are 15 girls and a total of 27 students in the class so we take the probability by doing 15/27. We can narrow both the numerator and the denominator using 3 which gives us 5/9. Therefore, the best option that fits our scenario is option C, 5/9.
Finally, looking at the last question, it's asking what the theoretical probability that the coin will land on heads on the next toss. Theoretical probability doesn't consider how much times Murray tossed the coin, the only thing it cares about is what the actual probability of tossing a coin is. Therefore that makes it a 50% chance of landing on a heads and a 50% chance of landing on a tails. The best option that first our scenario is option B, 1/2.
<u><em>Hope this helps! Let me know if you have any questions</em></u>
