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Vlada [557]
3 years ago
8

What is the simple interest that is missing from the table? Use the formula /=prt

Mathematics
2 answers:
Fiesta28 [93]3 years ago
7 0

Answer: The correct answer everyone is looking for is 450.40

Step-by-step explanation:  

You are very welcome would help it would help alot

if you give me Brainliest it would help and if you have any questions comment them

sdas [7]3 years ago
5 0
450 because I trim the test and I k ow the answer
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In a right triangle ABC,right angled at B,the ratio of AB to AC is 1:root 2.Find the value of 2tanA/1-tan square A
Helen [10]
Since we know that ratio of AB : AC is 1 : √2, then we can more or less use those values for the sides, check the picture below.

so we're really looking for tan(2A).  Let's bear in mind that tan²(θ) is just another way to write [ tan(θ) ]².

\bf \stackrel{\textit{Double Angle Identities}}{tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}}\\\\
-------------------------------\\\\
tan(2A)=\cfrac{2tan(A)}{1-tan^2(A)}\implies \cfrac{2\left( \sqrt{2} \right)}{1-(\sqrt{2})^2}\implies \cfrac{2\sqrt{2}}{1-2}\implies -2\sqrt{2}


8 0
4 years ago
Courses
madreJ [45]

Answer:

Box-plot = {54, 65, 69, 73, 76}

Step-by-step explanation:

The data provided for the number of desks on each floor of Texter Corporate is as follows:

S = {54, 60, 65, 66, 67, 69, 70, 72, 73, 75, 76}

There are a total of n = 11 floors.  

A boxplot, also known as a box and whisker plot is a method to demonstrate the distribution of a data-set based on the following 5 number summary,

Minimum (shown at the bottom of the chart)

First Quartile (shown by the bottom line of the box)

Median (or the second quartile) (shown as a line in the center of the box)

Third Quartile (shown by the top line of the box)

Maximum (shown at the top of the chart).

Arrange the data in ascending order as follows:

S': = {54 , 60 , 65 , 66 , 67 , 69 , 70 , 72 , 73 , 75 , 76}

The minimum value is:

Minimum = 54

The maximum value is:

Maximum = 76

As there are odd number of values the median is the middle value.

Median = 6th value = 69

The first quartile is the median of the first half of the data.

S'₁ = {54 , 60 , 65 , 66 , 67}

First quartile = 3rd value = 65

The third quartile is the median of the second half of the data.

S'₂ = {70 , 72 , 73 , 75 , 76}

Third quartile = 3rd value = 73

Thus, summarized data for the box plot is:

Box-plot = {54, 65, 69, 73, 76}

8 0
3 years ago
How to tell if a piecewise function is differentiable.
harina [27]

Answer:

So what we're going to do is now take the so drdx of negative 3x plus 1 is equal drdx of x squared

Step-by-step explanation:

3 0
3 years ago
Can someone help me with these 5 questions
svetlana [45]

Answer: 1. 2x + 8

2. 11x + 9

3. -9x + 23

4. -62

5. -13x + 11

5 0
3 years ago
In the diagram of circle O, m NQM  103
-BARSIC- [3]

Answer:

88 degree

Step-by-step explanation:

We assume the measure of MN is x degree.

As the measure of LP is 30 degree more than that of MN, so that the measure of LP is: x + 30 degree

In the circle, as 4 points M,N,P,L are on the circle, we have:

+) ∡MPN = 1/2 * (measure of ∡MPQMN) = x/2 = ∡MPQ

+) ∡LMP =1/2 * (measure of LP) = (x+30)/2 = ∡QMP

We have ∡NQM and ∡MQP are complementary angles, so that:

∡MQP + ∡NQM = 180

=> ∡MQP = 180 - ∡NQM = 180 -103 = 77

In the triangle QMP, total measure of 3 internal angles are 180 degree, so that:

∡MQP + ∡QMP + ∡MPQ = 180

=> 77 + (x + 30)/2 + x/2 = 180

=> 77 + x/2 + 15 + x/2 = 180

=> x = 180 -77-15= 88

So that the measure of MN is 88 degree

5 0
3 years ago
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