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igor_vitrenko [27]
3 years ago
10

The division algorithm states that if​ p(x) and​ d(x) are polynomial functions with d left parenthesis x right parenthesis not e

quals 0 comma and the degree of​ d(x) is less than or equal to the degree of​ p(x), then there exist unique polynomial functions​ q(x) and​ r(x) such that
Mathematics
2 answers:
katrin [286]3 years ago
7 0

Answer:

In a division algorithm, p(x) refers to the dividend polynomial, d(x) refers to the divisor polynomial, q(x) refers to the quotient polynomial and r(x) refers to the residula polynomial.

The division algorithm is defined as

p(x)=d(x) \times q(x) +r(x)

Where p(x)\geq d(x) and d(x) \neq 0, other wise the algorithm won't be defined.

So, the complete paragraph is: "if p(x) and d(x) are polynomial functions with d(x)\neq 0 and the degree of d(x) is less than or equal to the degree of p(x), then there exist unique polynomial functions q(x) and r(x) such that  p(x)=d(x) \times q(x) +r(x).

mamaluj [8]3 years ago
5 0

Answer:

I guess you ran out of space

Step-by-step explanation:

I think you have to prove that you get a line. Just take the limit of the resulting remainder. That goes to zero.

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8. Solve the following proportion (1 point)
Arturiano [62]

Answer:

97.5

Step-by-step explanation:

Cross multiply

2 * x = 2x

15 * 13 = 195

2x = 195

2x/2 = 195/2

x = 97.5

[RevyBreeze]

6 0
2 years ago
Read 2 more answers
1. Make sure your answers and work is SHOWN please and steps are in order.
JulijaS [17]

Been a while since I've done synthetic division.

1a. Let's assume that's supposed to be an equals sign

p(x) = 2x⁴ - 3x³ - 6x² + 5x + 6

possible rational roots have factors of 6 in the numerator and of 2 in the denominator.  We'll only worry about negative numerators.

Factors of six: 1,2,3,6, and we don't forget -1,-2,-3,-6

Factors of 2: 1,2

Possible rational roots:

(dividing by 1:) 1,-1,2,-2,3,-3,6,-6

(dividing by 2:) 1/2, -1/2  (2/2=1 is a duplicate, don't have to repeat it), 3/2, -3/2

Possible rational roots: 1,-1,2,-2,3,-3,6,-6, 1/2, -1/2, 3/2, -3/2

Synthetic division, trying x=1,

   1 | 2  -3  -6  5  6

             2  -1  -7  -2

       2    -1  -7  -2  4

Got a remainder of 4, so 1 isn't a root;

Trying x=-1  

-1 | 2  -3  -6  5  6

         -2   5  1  -6

     2  -5  -1  6  0

Zero remainder, found a root, x=-1.  This division says

(2x⁴ - 3x³ - 6x² + 5x + 6) / (x + 1) = 2x³ - 5x² - x + 6

Same set of rational roots on the cubic, we continue with x=2

2 | 2 -5 -1 6

         4 -2 -6

    2  -1 -3 0

Another zero remainder, x=2 is a root.  We're left with 2x² - x - 3 = 0, which factors as

(2x - 3)(x + 1) = 0

That's a second factor of x+1.  Our final factorization is

2x⁴ - 3x³ - 6x² + 5x + 6 = (x + 1)²(x-2)(2x - 3)

Fourth degree with a positive leading coefficient so goes to +infinity at both ends.  Double zero at x=-1, so it's tangent there, just touching the x axis, then down through x=3/2 and up through x=2.  

I'll leave the actually sketching and the other two polynomials to you -- that took some time.

4 0
3 years ago
For the function f(x) and g(x) given in the graph. Find f(g(2))
Katen [24]

Answer:

f(g(2)) = 4

Step-by-step explanation:

find g(2) then substitute the value obtained into f(x)

locate x = 2 on the x- axis, go vertically up to meet g(x) at (2, 5 )

locate x = 5 on the x- axis, go vertically up to meet f(x) at (5, 4 )

then f(g(2)) = 4

3 0
2 years ago
What is the cotangent of Angle Q !! look at the pic for answer choices and the triangle
vfiekz [6]
√29/2 since cotangent deals the reciprocal of tangent and cotangent value is adjacent side/opposite side
8 0
2 years ago
14. Order the following from least to greatest. Angles ∠B, ∠C, ∠BDC. Sides DE, EF, and DF (Choose one for Angles and one for Sid
Veronika [31]

Answer:

gggggggggggggggggggggggggggg

Step-by-step explanation:

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3 0
3 years ago
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